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prohojiy [21]
3 years ago
6

Photographs are taken of falling drops of two different liquids: Liquid X Liquid Y Note: the drops have identical volumes. Notic

e that the oncoming wind tends to flatten out each drop as it falls. What's different about liquids X and Y
Chemistry
1 answer:
aliina [53]3 years ago
7 0

Answer:

See explanation

Explanation:

The reason why the droplets are spherical is  the surface area to volume ratio of the falling droplet in a gravitational field. Recall that a sphere has a small surface area to volume ratio.

Between X and Y, one key difference that will define the rate at which the two drops of liquid falls is the viscosity of the fluid. Since the images were not attached, I can not really tell what liquid droplet is more flatter  than the other.

However, the liquid with a greater surface tension will form larger droplets and experience a greater air resistance as the droplet falls. Hence the less the surface tension, the flatter the droplets. Cohesive forces pull molecules of a liquid droplets inwards leading to a more spherical shape and reducing the surface area. Surface tension is therefore the reason why liquids form droplets.

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20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator
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Answer:

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

Bromocresol green, color change from pH = 4.0 to  5.6

Explanation:

The equation for the reaction is :

C_2H_5NH_2_(_a_q_)     +     H^+_(_a_q_)   ---      C_2H_5NH_{3(aq)}^+

concentration of C_2H_5NH_{2(aq) = 10%

10 g of C_2H_5NH_{2(aq) in 100 ml solution

molar mass = 45.08 g/mol

number of moles = 10 / 45.08

= 0.222 mol

Molarity of C_2H_5NH_2(aq) = 0.222 \times \frac{1000}{100}mL

= 2.22 M

number of moles of C_2H_5NH_{2(aq) in 20 mL can be determined as:

= 20 mL \times  2.22 M= 44*10^{-3} mole

Concentration of C_2H_5NH_2(aq) = \frac{44*10^{-3}*1000}{20}

= 2.22 M

Similarly, The pKa Value of C_2H_5NH_{2(aq) is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

the pH value at equivalence point is,

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pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]

pH = 5.21

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

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