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NemiM [27]
2 years ago
8

If you start with 4 moles of iron and 3 moles of oxygen to produce iron oxide, what is the limiting reagent? (You will need to b

alance the equation first.) Fe + O2 -> Fe2O3
A. they are equal
B.Fe
C. O2
D.Fe2O3​
Chemistry
1 answer:
Marianna [84]2 years ago
8 0

The correct statement regarding the limiting reactant for the reaction between 4 moles of iron and 3 moles of oxygen is: They are both equal. (Option A)

<h3>Balanced equation</h3>

We'll begin by writing the balanced equation for the reaction between iron and oxygen. This is given below:

4Fe + 3O₂ --> 2Fe₂O₃

SUMMARY

From the balanced equation above,

4 moles of Fe reacted with 3 moles of O₂

<h3>How to determine the limiting reactant</h3>

The limiting reactant is the reactant that is consumed completly in a chemical reaction.

The limiting reactant can be obtain as illustrated below:

From the balanced equation above,

4 moles of Fe reacted with 3 moles of O₂

From the illustration above, we can see that 3 moles of Fe required 4 moles of O₂ for complete reaction.

Thus, Fe and O₂ are both the limiting reactant.

Therefore, we can conclude that Fe and O₂ are equal

Learn more about stoichiometry:

brainly.com/question/11587316

#SPJ1

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When scientist find new species that may have to change classification systems in order to accommodate them. DNA sequencing has also let us find out more about evolutionary relationships. The more recent the common ancestor, the more closely related the two species are.

Explanation:

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Its gelatin and a fruit cup the same (its for a project)
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Answer:

No

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2 years ago
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How many grams of sulfur must be burned to give 100.0 g of So2
andriy [413]

Answer:

50 g of S are needed

Explanation:

To star this, we begin from the reaction:

S(s) + O₂ (g) →  SO₂ (g)

If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.

According to stoichiometry, we can determine the moles of sulfur dioxide produced.

100 g. 1mol / 64.06g = 1.56 moles

This 1.56 moles were orginated by the same amount of S, according to stoichiometry.

Let's convert the moles to mass

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4 0
3 years ago
Hydrazine, N2H4, may react with oxygen to form nitrogen gas and water.
Sindrei [870]

Answer:

The percent yield of the reaction is 35 %

Explanation:

In the reaction, 1 mol of hydrazine reacts with 1 mol O₂ to produce 1 mol of nitrogen and 2 moles of water.

Let's verify the moles that were used in the reaction.

2.05 g . 1mol/ 32 g = 0.0640 mol

In the 100% yield, 1 mol of hydrazine produce 1 mol of N₂ so If I used 0.0640 moles of reactant, I made 0.0640 moles of products.

Let's use the Ideal Gases Law equation to find out the real moles of nitrogen, I made (real yield).

1atm . 0.550L = n . 0.082 . 295K

(1atm . 0.550L) / 0.082 . 295K = n → 0.0225 moles

Percent yield of reaction = (Real yield / Theoretical yield) . 100

(0.0225 / 0.0640) . 100 = 35%

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