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3 years ago

Help fast please lol

Mathematics

1 answer:

igomit [66]3 years ago

6 0

Answer:

Between 0 and 3: decreasing

Between 3 and 4: constant (stays the same)

Between 4 and 8: decreasing

Step-by-step explanation:

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Guys plssssssss! I want to spend time today and tomorrow with my fam before they go back to Washington

Andru [333]

Answer:

IF its a pretest the grade doesnt count im pretty sure.

3 0

3 years ago

Read 2 more answers

Drag the correct steps into order to solve the equation 6x+6= -12 for x

damaskus [11]

Answer:

x = -3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 6 from both sides:

6x + 6 (-6) = -12 (-6)

6x = -12 - 6

6x = -18

Isolate the variable, x. Divide 6 from both sides:

(6x)/6 = (-18)/6

x = (-18)/6

x = -3

x = -3 is your answer.

8 0

3 years ago

Give the equation of the line, perpendicular to the line with equation y=2x+1, that passes

katrin [286]

Answer:

y=-1/2x+2

Explanation:

8 0

3 years ago

HELP!!!!!!!!! ME!!!!!!!!! HELP!!!!

Gala2k [10]

Correct answer is the last one.
Function because for every x only one value of y,
not one-to-one because, 2 values of x have the same value of y.

7 0

4 years ago

Diana put $8000 in a 10-year CDpaying 5% interest compoundedmonthly. After 2 years, shewithdrew all her money, and as anearly wi

Svet_ta [14]

Answer:

$8,430.23

Explanation:

From the statement of the problem:

• The principal amount = $8,000

• Interest Rate = 5%

• Compounding Period = 12 (Monthly)

The compound interest formula is given as:

$A(n)=P\left(1+\frac{r}{k}\right)^{nk}$

Using the compound period formula, we first, calculate the amount in her account at the end of 1 year.

$\begin{gathered} A(1)=8000\left(1+\frac{0.05}{12}\right)^{12\times1} \\ A(1)=\$8409.30 \end{gathered}$

This means that the interest she made during the first year is:

$\text{ Interest during the first year}=8409.30-8000=\$409.30$

Next, calculate the amount in her account at the end of the second year.

$\begin{gathered} A(2)=8000\left(1+\frac{0.05}{12}\right)^{12\times2} \\ A(2)=\$8839.53 \end{gathered}$

Since she paid back all the interest she made during the first year, the amount Diana was left with is:

$\begin{gathered} 8839.53-409.30 \\ =8,430.23 \end{gathered}$

Diana was left with $8,430.23.

6 0

1 year ago