Short Answer: B
Remark
The area of any triangle is
A = 1/2 b * h
b = 7 3/4
h = 4 2/3
Step one
Convert all fractions to improper fractions.
7 3/4 = (28 + 3) / 4 = 31/ 4
4 2/3 = (12 + 2) / 3 = 14/3 Now multiply
Step Two
Multiply
Area = 1/2 * 31/4 * 14/3 Multiply the numerators together and then the denominators.
Area = (1 * 31 * 14) / (2 * 4 * 3) = 434 /24
Step 3
Convert this to a whole number + a fraction
Area = 18 + 0.08333333 You already have your answer. It is B because only B gives an answer of 18. But you can get the rest of
Let x = 0.083333333
100 x = 8.3333333333
<u>x = 0.0833333333 </u> Subtract
99 x = 8.25 Divide by 3 on both sides.
33 x = 2.75 Divide by 11
3x = 0.25
x = 0.25/3 Multiply top and bottom by 4
x = 1 / 12
The answer is 18 1/12.
Answer:
x = -13/5
Step-by-step explanation:
let x be the number
8x + 6 = 3x - 7
move variables to left and numbers to right
8x - 3x = - 7 -6
5x = -13
x = -13/5
-10x + 20 should be the right answer.
The inverse would make the inputs the outputs (switching the x's and y's) because plugging in 4 into the inverse would somehow output 4 and 5, the inverse could not exist. plug in the inverse points to see that the vertical line test would fail.
Answer:
Part 1
Type II error
Part 2
No ; is not ; true
Step-by-step explanation:
Data provided in the question
Mean = 100
The Random sample is taken = 43 students
Based on the given information, the conclusion is as follows
Part 1
Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis
Based on this, it is a failure to deny or reject the false null that represents type II error
Part 2
And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible
Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful
