Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
<span>Let x = amt of water evaporated :.05(50) = .08(50-x) 2.5 = 4 - .08x .08x = 4 - 2.5 .08x = 1.5 x = 18.75 lb of water evaporated : ; Check; amt of salt remains the same, only the percentage is different, right? .05(50) = .08(50-18.75) .05(50) = .08(31.25) 2.5 = 2.5</span>
Can't see the answer choices but Nicola is wrong. 16 * (12/8) = 24>16
This is a right triangle, the measure of angle A is 90 degrees.
First thing to do I guess is finding B and C.
tan^-1 (7/12) = 30 degrees
tan^-1 (12/7) = 60 degrees
60 + 30 = 90
180 - 90 = 90. Therefore angle A = 90 degrees
