100-35 = 65
65% de 2300 = 1495 (mes 1)
2300-1495 = 805 (mes 2)
65% de 805 = 523,25 (mes 3)
65% de 523,25 = 340,1125 ~ 340,10 (mes 4)
35000, rounding down from five.
Calculate the z-score for the given data points in the item using the equation,
z-score = (x - μ) / σ
where x is the data point, μ is the mean, and σ is the standard deviation.
Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2
This translates to a percentile of 2.28%.
(54.9) z-score = (54.9 - 52.5)/2.4 = 1
This translates to a percentile of 84.13%.
Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>
Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.
Answer:C
Step-by-step explanation:45
