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ValentinkaMS [17]
2 years ago
6

What negative value of x makes the equation | 4x + 6 = 2x + 27 true?

Mathematics
1 answer:
Alex Ar [27]2 years ago
3 0

Answer:

do multiple choice

Step-by-step explanation:

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maksim [4K]

Answer:

the base is 7 units and the height is 3 units

5 0
3 years ago
Solve the equation v+5/-9 - 4 = -6/8
tamaranim1 [39]
First you simplify both sides of the equation to make v+-41/9=-3/4.

Then add -41/9 to both sides to get the answer which is 137/36

v=137/36
4 0
3 years ago
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
Select whether each statement shows an example of the
xz_007 [3.2K]
1.no should b 8x + 20
2.no should be 21x + 14
3.yes
3.yes
4 0
3 years ago
Read 2 more answers
Help? Solve the system of equations.<br><br> y = 3x<br> y = x2 + 3x – 16<br> solutions: ( );( )
mote1985 [20]

Answer:

(- 4, - 12 ) , (4, 12 )

Step-by-step explanation:

Given the 2 equations

y = 3x → (1)

y = x² + 3x - 16 → (2)

Substitute y = x² + 3x - 16 into (1)

x² + 3x - 16 = 3x ( subtract 3x from both sides )

x² - 16 = 0 ( add 16 to both sides )

x² = 16 ( take the square root of both sides )

x = ± \sqrt{16} = ± 4

Substitute these values into (1) for corresponding values of y

x = - 4 : y = 3 × - 4 = - 12 ⇒ (- 4, - 12 )

x = 4 : y = 3 × 4 = 12 ⇒ (4, 12 )

6 0
3 years ago
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