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Troyanec [42]
3 years ago
13

I will mark u brainlist

Physics
2 answers:
dedylja [7]3 years ago
7 0

Answer:

DragonFly or a dog

Explanation:

Damm [24]3 years ago
6 0
The dog does not go through metamorphosis.
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Jupiter and uranus both _____. have two satellites rotate backwards orbit faster than they revolve have rings and bands
mina [271]
The answer is:  [D]:  "have rings and bands" .
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7 0
3 years ago
Starting from rest, a racecar moves 112 m in the first 7 s of uniform acceleration. What is the car's acceleration?​
Leviafan [203]

Answer:

215mph

Explanation:

multiply 112milws by 2 and multiple that by seven, then divide it by two

6 0
2 years ago
Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s
Mekhanik [1.2K]

Answer:

10

Explanation:

Given that :

Initial Velocity (u) = 25 m/s

Range can be obtained using the relation :

Range = (u² * sin2θ) / g

g = 10m/s ; θ = 45

Range = [10² * sin2(45)] / 10

Range = [100 * 1] ÷ 10

Range = 10

5 0
3 years ago
65 Points! 9 Questions!
alekssr [168]

Answer:

energy : the ability to cause change

work : is force x distance or when an object moves a distance due to a specific force (measured in units of newtons-meters)

potential energy  : is stored energy

kinetic energy : is energy in motion

mechanicle energy : the energy of motion such as a moving vechile

thermal energy : total kinetic energy in moving partsticles, like in boiling water (energy of heat)

chemical : energy stored in chemical bonds, like in plants

electromagnetic : waves with electric and magnetic properties , such as light

nuclear energy : energy stored in the nuclear atoms

all dish was from mah brain u better mark meh brainliest >:}

~batmans wife dun dun dun...aka ~serenitybella

5 0
4 years ago
Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB 23.4 km/hr. at t
marshall27 [118]

Answer:

        x = 240 m

Explanation:

This is a kinematics exercise

Let's fix our frame of reference on car A

           x = x₀ₐ+ v₀ₐ t + ½ aₐ t²

         

the initial position of car a is zero

           x = 0 + v₀ₐ t + ½ 0.8 t²

for car B

          x = x_{ob} + v_{ob} t - ½ a_b t²

     

car B's starting position is 30 m

         x = 30 + v_{ob} t - ½ 0.4 t²

at the point where they meet, the position of the two vehicles is the same

         0 + v₀ₐ t + ½ 0.8 t² = 30 + v_{ob} t - ½ 0.4 t²

let's reduce the speeds to the SI system

        v₀ₐ = 14.4 km / h (1000 m / 1 km) (1h / 3600s) = 4 m / s

        v_{ob} = 23.4 km / h = 6.5 m / s

        4 t + 0.4 t² = 30 + 6.5 t - 0.2 t²

        0.2 t² - 2.5 t - 30 = 0

        t² - 12.5 t - 150 = 0

we solve the quadratic equation

       t = \frac{12.5 \pm \sqrt{12.5^2 + 4 \ 150}  }{2}

       t = \frac{12.5 \  \pm 27.5}{2}

       t₁ = 20 s

       t₂ = -7.5 s

time must be a positive quantity so the correct result is t = 20 s

let's look for the distance

        x = 4 t + ½ 0.8 t²

        x = 4 20 + ½ 0.8 20²

        x = 240 m

8 0
3 years ago
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