Answer:
Ethylene glycol
HOCH₂CH₂OH
Explanation:
For the molecules in the question, the viscosity will rise with the number of hydrogen bonds that can be formed.
A hydrogen bond is a week physical bond which is formed when hydrogen is found between atoms with high electronegativity (oxygen, nitrogen, fluorine):
O-H ··· O, N-H ··· O, N-H ··· O, O-H ··· N, F-H ··· F and so on.
Here we have have two compounds that can form hydrogen bonds (between themselves):
C) ethanol and D) ethylene glycol
Ethylene glycol have more hydroxide groups (-OH) than the ethanol so it will form more hydrogen bonds thus increasing its viscosity.
Answer:
kg & m/s
Explanation:
mass is measured in kg and speed is measured in m/s
0.139 moles of plutonium are present in a sample containing 8.4 x 10²² atoms of Pt.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated using the following expression:
no of moles = no of molecules ÷ 6.02 × 10²³
According to this question, 8.4 × 10²² atoms of plutonium are present in the molecule of plutonium.
no of moles = 8.4 × 10²² = 6.02 × 10²³
no of moles = 1.39 × 10-¹
no of moles = 0.139moles
Therefore, 0.139 moles of plutonium are present in a sample containing 8.4 x 10²² atoms of Pt.
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Answer:
1. Metals (H)
2. Nonmetals (K)
3. Period (P)
4. Family (C)
5. Metaloids (E)
6. Menedleev (M)
7. Halogens (D)
8. Alkalai (A)
9. Transitional Metal (T)
10. No Family Name (M)
11. Noble Gas (P)
12. Alkaline Earth Metals (B)
Answer:
a) 2.6 mole of O2 per mole of methane
b) 9.78 mole of N2 per mole of methane
c) Mole fraction of H2O = 0.33
d) 6.12 mole of H2O pero mole of methane
Explanation:
The first thing you have to do is the balanced reaction of the methane combustion:
CH4 +2 O2 -->2 H2O + CO2
You calculate the moles of O2 needed to react with 1 mole of methane and add the excess factor
2 x 1.3 = 2.6 moles of O2
For the N2 moles you calculate it with the air composition (21 % O2, 79% N2)
2.6 moles of O2 * 0.79/0.21 = 9.78 moles of N2
With the total stream of air = 12.38 moles you add the humidity factor
12.38 * 1.5 = 18.57 moles So 6.12 are moles of H20 entering per mole of CH4.
To calculate the mole fraction yo divide the moles of water among the moles of the stream:
6.12/18.57 --> 0.33
