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3 years ago

How many molecules are in 2CaCO3 and 4O2

Chemistry

1 answer:

Fed [463]3 years ago

5 0

Answer:

2Ca: 2, C: 1, O3: 3, 2 + 1 + 3 = 6

I did some research and there are no further info on how many there are

I hope this helps

know you will do great!!

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When you blow dry your hair is it physical or chemical change

viva [34]

When you blow dry your hair you will get a physical change

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4 years ago

Read 2 more answers

How many moles are represented by 3.01 - 1023 helium atoms?

Pavlova-9 [17]

Answer:

0.5 mol

Explanation:

Given data:

Number of atoms of He = 3.01 ×10²³

Number of moles = ?

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.02 × 10²³ is called Avogadro number.

1 mole = 6.02 × 10²³ atoms

3.01 ×10²³ atoms × 1 mol / 6.02 × 10²³ atoms

0.5 mol

7 0

3 years ago

If the distance between two objects is increased, the gravitational force will _____.

Mila [183]

Answer:

Decrease by the distance squared

Explanation:

Gravitation formula:

$F=\frac{GMm}{r^{2}}$

where

'F' is the force of attraction between the two bodies (Gravitational force),

'G' is the universal gravitational constant,

'M' is the mass of the first object,

'm' is the mass of the second object and

'r' is the distance between the centers of each object.

Hence, with the increase by distance between two objects , the gravitation decreases by the distance squared

7 0

3 years ago

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Calculate the volume of chlorine at stp that would be required to act completely with 3.70g of dry slaked line

myrzilka [38]

Answer:

The volume required is 2.24L

Explanation:

The slaked lime Ca(OH)2, reacts with chlorine, Cl2, as follows:

6Cl₂(g) + 3Ca(OH)₂(s) → Ca(ClO₃)₂ (aq) + 2CaCl₂ (aq) + 6HCl (aq)

Where 6 moles of chlorine react with 3 moles of slaked llime,

To solve this question we must find the moles of slaked lime added. With these moles we can find the moles of chlorine required and its volume at STP as follows:

Moles Ca(OH)2 - Molar mass: 74.093g/mol-

3.70g * (1mol / 74.093g) = 0.0500 moles Ca(OH)2

Moles Cl₂:

0.0500 moles Ca(OH)2 * (6 mol Cl₂ / 3 mol Ca(OH)2) =

0.100 moles Cl₂

Now using PV = nRT

nRT / P = V

Where n are moles: 0.100 moles

R is gas constant = 0.082atmL/molK

T is absolute temperature = 273K at STP

P is pressure = 1atm at STP

And V is volume, our incognite:

0.100mol*0.082atmL/molK*273K / 1atm = V

2.24L = Volume of Cl₂

<h3>The volume required is 2.24L</h3>

8 0

3 years ago

If 80.0 grams of oxygen gas is consumed with a stoichiometric equivalent of aluminum metal, how many grams of aluminum oxide (mo

Pachacha [2.7K]

Answer:

170 g

Explanation:

Moles of Oxygen gas :

Given, Mass of Oxygen = 80.0 g

Molar mass of Oxygen gas= 31.998 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{80.0\ g}{31.998\ g/mol}$

$Moles\ of\ O_2=2.5\ mol$

The reaction between Al and O₂ is shown below as:

4Al + 3O₂ ⇒ 2Al₂O₃

From the reaction,

3 moles of O₂ on reaction forms 2 moles of Al₂O₃

1 mole of O₂ on reaction forms 2/3 moles of Al₂O₃

2.5 moles of O₂ on reaction forms (2/3)*2.5 moles of Al₂O₃

Moles of Al₂O₃ = 1.6667 moles

Molar mass of Al₂O₃ = 102 g/mol

Mass = Moles * Molar mass = 1.6667 * 102 g = 170 g

8 0

3 years ago