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Alexxandr [17]
3 years ago
5

What did Rutherford's gold-foil experiment help him conclude?

Chemistry
2 answers:
Svetach [21]3 years ago
8 0
C. mass is protons and neutrons. Both are in the nucleus
GREYUIT [131]3 years ago
8 0

Answer:

That experiment led not only him but scientists in general to conclude and to prove that the atom's nucleous is not solid, proving Thomson's Plum Pudding model wrong and contradicting that previous hypothesis since the beam of positively charged particles pierced and ran through the foil, thus the volume of the atom is mostly unoccupied, setting up the fundamentals of what until these days is the concept of an atom. The most suitable answer would be then <em>C</em>.

Explanation:

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If a beaker of water and a beaker of acetic acid are at the same elevated temperature, which will cool more quickly to room temp
4vir4ik [10]
The beaker of acetic acid will cool more quickly.

The specific heat capacity of acetic acid is about half that of water.
Thus, it takes twice as much heat gain (or loss) in acetic acid to cause a given change in temperature.
If everything else is constant and heat is being lost at the same rate, the temperature of the acetic acid should drop twice as fast as that of water.
4 0
3 years ago
In the following overall chemical reaction, aluminum displaces chromium from chromium(III) oxide and forms aluminum oxide.
mafiozo [28]

Answer:

Change in enthalpy for the reaction is -536 kJ

Explanation:

  • Overall chemical reaction can be represented a summation of two given elementary steps with slight modification.
  • Take reaction (1a) and divide stoichiometric coefficients by 2
  • Take reverse reaction (2a) and divide stoichiometric coefficient by 2
  • Then add these two modified elementary steps to get overall chemical reaction
  • \Delta H is an additive property. hence value of \Delta H will be changed in accordance with modification

2Al+\frac{3}{2}O_{2}\rightarrow Al_{2}O_{3}.....\Delta H_{1}=\frac{-3351.4}{2}kJ=-1675.7kJ

Cr_{2}O_{3}\rightarrow 2Cr+\frac{3}{2}O_{2}....\Delta H_{2}=\frac{2279.4}{2}kJ=1139.7kJ

--------------------------------------------------------------------------------------------------------------

2Al+Cr_{2}O_{3}\rightarrow 2Cr+Al_{2}O_{3}....\Delta H=\Delta H_{1}+\Delta H_{2}=-1675.7+1139.7kJ=-536kJ

6 0
3 years ago
The energy source used in nuclear power plants today is
Klio2033 [76]

Answer:

B I have taken the quiz already 90%

7 0
3 years ago
The area of a triangle with a base of 4 meters and a height of 6 meters.
Tanya [424]

Answer: I believe the answer is 12

Explanation:

8 0
3 years ago
Read 2 more answers
What is the wavelength of a photon with an energy of 3.38 x 10-19 J?
irina1246 [14]

Answer:

C. 588 nm

Explanation:

Given parameters:

Energy of the photon  = 3.38 x 10⁻¹⁹J

Unknown:

Wavelength of the photon   = ?

Solution:

The energy of a photon can be expressed as;

     E = \frac{hc}{wavelength}

    hc  = E x wavelength

     Wavelength  = \frac{hc }{E}  

  h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

  c is the speed of light  = 3 x 10⁸m/s

  E is the energy  

   Wavelength = \frac{6.63 x 10^{-34} x 3 x 10^{8} }{3.38 x 10^{-19} }    = 5.89 x 10⁻⁷m

4 0
3 years ago
Read 2 more answers
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