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2 years ago

What did Rutherford's gold-foil experiment help him conclude?

Chemistry

2 answers:

Svetach [21]2 years ago

8 0

C. mass is protons and neutrons. Both are in the nucleus

GREYUIT [131]2 years ago

8 0

Answer:

That experiment led not only him but scientists in general to conclude and to prove that the atom's nucleous is not solid, proving Thomson's Plum Pudding model wrong and contradicting that previous hypothesis since the beam of positively charged particles pierced and ran through the foil, thus the volume of the atom is mostly unoccupied, setting up the fundamentals of what until these days is the concept of an atom. The most suitable answer would be then <em>C</em>.

Explanation:

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Marcar la alternativa correcta en relación a desplazamiento y la distancia

asambeis [7]

Answer A

Explanation:

8 0

2 years ago

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Anna71 [15]

Answer:

31.652g of Na3PO4

Explanation:

We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:

Na3PO4 will dessicate in solution as follow:

Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.

Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e

xM Na3PO4 = (1.10 x 1)/3

xM Na3PO4 = 0.367M

Therefore, the molarity of Na3PO4 is 0.367M.

Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:

Molarity of Na3PO4 = 0.367M

Volume = 525mL = 525/1000 = 0.525L

Mole of Na3PO4 =..?

Molarity = mole /Volume

0.367 = mole /0.525

Cross multiply

Mole of Na3PO4 = 0.367 x 0.525

Mole of Na3PO4 = 0.193 mole.

Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:

Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol

Mole of Na3PO4 = 0.193 mole

Mass of Na3PO4 =.?

Mass = mole x molar mass

Mass of Na3PO4 = 0.193 x 164

Mass of Na3PO4 = 31.652g

Therefore, 31.652g of Na3PO4 is needed to prepare the solution.

6 0

2 years ago

A 20.0 g piece of a metal is heated and place into a calorimeter containing 250.0 g of water initially at 25.0 oC. The final tem

BartSMP [9]

Answer:

$Q_{metal} = -6799\,J$

Explanation:

By the First Law of Thermodynamics, the piece of metal and water reaches thermal equilibrium when water receives heat from the piece of metal. Then:

$Q_{metal} = - Q_{w}$

$Q_{metal} = m_{w} \cdot c_{p,w}\cdot (T_{1}-T_{2})$

$Q_{metal} = (250\,g)\cdot \left(4.184\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (25\,^{\textdegree}C - 31.5\,^{\textdegree}C)$

$Q_{metal} = -6799\,J$

6 0

3 years ago

Read 2 more answers

In the following reactions identify which substances are solid (s) or aqueous (aq). 1. Li,SO4( aq ) + MgCl, ( aq ) - 2LICI ( 2LI

IrinaK [193]

Answer:

Explanation:

4 0

2 years ago

What is the percent composition of hydrogen in NH4HCO3?

Readme [11.4K]

To find the Percent Composition of an atom, you use this formula:
Mass of element in the compound you're studying on ( in this case it's 5 since there is 5 Hydrogens) over the mass of the compound (which is here 79), Multiplied by 100 since you want a percent.
So we get:
$\frac{5}{79} * 100$
So you get about:
$0.063 * 100$
$6.3$

So, the percent composition of Hydrogen in NH4HCO3 is 6.3%

Hope this Helps! :D

7 0

3 years ago

Read 2 more answers