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3 years ago

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What is the molarity of ZnCl, that forms when 20.0 g of zinc completely reacts with CuCl2, according to the following reaction?

Assume a final
volume of 285 mL

Zn(s) + CuCl2(aq) → ZnCl2(aq) + Cu(s)

1 answer:

laila [671]3 years ago

8 0

1.61m :) use the photo below

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Dilute 0.407M & 2.56L solution to 7.005L. CF?

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Answer:

C₂ = 0.149 M

Explanation:

Given data:

Initial concentration = 0.407 M

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Formula:

C₁V₁ = C₂V₂

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V₁ = Initial volume

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V₂ =Final volume

Now we will put the values.

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What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v

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Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is $\lambda$ .

Formula to calculate thickness of a benzene thin film is as follows.

Optical path length through benzene ( $\lambda$ ) = $2 \times n \times d$

Hence, substituting the given values into the above formula as follows.

Optical path length through benzene = $2 \times n \times d$

d = $\frac{\text{Optical path length through benzene}}{2 \times n}$

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