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lana66690 [7]
3 years ago
7

What is the definition of a covelant bond?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

D. a bond between two atoms

A covelant bond is a bond formed by a sharing of a pair of electrons by two atoms.

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Making methanol the element hydrogen is not abundant in nature, but it is a useful reagent in, for example, the potential synthe
stealth61 [152]
ΔG⁰ = ΔH⁰ - TΔS
ΔH⁰ = Hf,(CH₃OH) - Hf,(CO) = -238.7 + 110.5 = -128.2 kJ/mol
ΔS = S(CH₃OH) - S(CO) - 2S(H₂) = 126.8 - 197.7 - 2 x 130.6 = -332.1 J/mol.K
So 
ΔG⁰ = - 128200 + 332.1 T
For the reaction to be spontaneous:
ΔG⁰ < 0
So: -128200 + 332.1 T < 0
332.1 T < 128200
T < 386.028 K
5 0
3 years ago
A 25.00 g solid sample of Ca(OH)2 was added into 1250 mL of 0.400 M HCl aqueous solution. The temperature of the solution was de
daser333 [38]

Answer:

86.735 kJ

Explanation:

Simply multiply the change in temperature by the Ccal;

(36.6 - 20.0)×5.225 = 86.735

5 0
3 years ago
Which of the metal is suitable to store lead nitrate solution​
kirill115 [55]

Explanation:

The nitrate anion is a univalent (-1 charge) polyatomic ion composed of a single nitrogen atom ionically bound to three oxygen atoms (Symbol: NO3) for a total formula weight of 62.05. Lead Nitrate is generally immediately available in most volumes.

3 0
3 years ago
Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

   H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)

Next we will calculate how many moles of H_2SO_4 are present in 85.00 mL of 1.500 M sulfuric acid.

As,       Molarity = \frac{\text{moles of solute}}{\text{liters of solution&#10;}}

            1.500 M = \frac{n}{0.08500 L&#10;}

                    n = 0.1275 mol H_2SO_4

Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

 0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})

                 = 21.42 g NaHCO_3

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

4 0
3 years ago
Hydrogen iodide can decompose into hydrogen and iodine gases. 2 HI(g) H2(g) + 12(g) Kp for the reaction is 0.016. If 0.350 atm o
solniwko [45]

Answer : The total pressure at equilibrium is 0.350 atm

Solution :  Given,

Initial pressure of HI = 0.350 bar

K_p = 0.016

The given equilibrium reaction is,

                             2HI(g)\rightleftharpoons H_2(g)+I_2(g)

Initially                  0.350           0       0

At equilibrium       (0.350-2x)    x       x

The total pressure at equilibrium = (0.350-2x)+x+x=0.350-2x+2x=0.350atm

Thus, the total pressure at equilibrium is 0.350 atm

4 0
3 years ago
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