ΔG⁰ = ΔH⁰ - TΔS
ΔH⁰ = Hf,(CH₃OH) - Hf,(CO) = -238.7 + 110.5 = -128.2 kJ/mol
ΔS = S(CH₃OH) - S(CO) - 2S(H₂) = 126.8 - 197.7 - 2 x 130.6 = -332.1 J/mol.K
So
ΔG⁰ = - 128200 + 332.1 T
For the reaction to be spontaneous:
ΔG⁰ < 0
So: -128200 + 332.1 T < 0
332.1 T < 128200
T < 386.028 K
Answer:
86.735 kJ
Explanation:
Simply multiply the change in temperature by the Ccal;
(36.6 - 20.0)×5.225 = 86.735
Explanation:
The nitrate anion is a univalent (-1 charge) polyatomic ion composed of a single nitrogen atom ionically bound to three oxygen atoms (Symbol: NO3) for a total formula weight of 62.05. Lead Nitrate is generally immediately available in most volumes.
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of
are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity = 
1.500 M = 
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of
to grams of
. As, the molar mass of
is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.
Answer : The total pressure at equilibrium is 0.350 atm
Solution : Given,
Initial pressure of
= 0.350 bar
= 0.016
The given equilibrium reaction is,

Initially 0.350 0 0
At equilibrium (0.350-2x) x x
The total pressure at equilibrium = 
Thus, the total pressure at equilibrium is 0.350 atm