Answer:
the water level was shallow beach, then it rose to deep sea, then the water receded to a beach
The answer would be m1 = m2
FBD of m1 is the sum of the forces in the y direction =
0
0 = T - m1*g
transposing:
m1*g = T
FBD of m2 is the sum of the forces in the y direction = 0
0 = T - m2*g
transposing:
m2*g = T
set them equal to each other and solve for m1
m1*g = m2*g
= m1 = m2
Explanation:
The force on individual mass would be downwards or descending
and equal to the tension shaped by the other mass, which would be upward or
rising by the act of the seamless pulley, so the forces cancel on each mass.
Answer;
V = 14.7 m/s
Explanation and solution;
Vx = V cos theta
Vx = 16m/s × cos 28.08
Vx = 14.1 m/s
Vy = Vsin theta
Vy = 7.51m/s
t = d/Vx
t = 16.8m/ 14.1
t= 1.191 s
Now, find Vy at t= 1.191
Vy = Vy - gt
Vy = 7.51 - 9.81*1.191
Vy = - 4.18 m/s
V = sqrt (Vy^2 +Vx^2)
V= sqrt (4.18^2 + 14.1^2)
V= 14.7m/s
Answer:
θ = 90º
Explanation:
The velocity is given by
v =
calculate
v = 3 i ^ + √2 j ^ + 2t k ^
acceleration is defined by
a = dv / dt
a = 2 k ^
one way to find the angle is with the dot product
v. a = | v | | a | cos θ
cos θ= v.a / | v | | a |
Let's look for the value of each term
v. a = 4 t
| v | = =
| a | = 2
they ask us for the angle for time t = 0
v. a = 0
| v | = √11 = 3.317
we substitute
cos θ = 0 /√11
cos θ = 0
therefore the angles must be θ = 90º