Answer: 3.13 m
Explanation:
Given
mas of the ball is m=10 kg
The ball rolls down a vertical distance of 5 m
Spring constant of spring is 
Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy
![\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m](https://tex.z-dn.net/?f=%5CRightarrow%20mgh%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2%5Cquad%20%5B%5Ctext%7Bx%3Dcompression%20in%20the%20spring%7D%5D%5C%5C%5C%5C%5CRightarrow%2010%5Ctimes%209.8%5Ctimes%205%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20100%5Ccdot%20x%5E2%5C%5C%5CRightarrow%20x%3D%5Csqrt%7B9.8%7D%5C%5C%5CRightarrow%20x%3D3.13%5C%20m)
Thus, the spring compresses by 3.13 m.
Answer:
<h3>The answer is 3.37 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula

From the question
force = 172 N
mass = 51 kg
We have

We have the final answer as
<h3>3.37 m/s²</h3>
Hope this helps you