Answer:
(a) F = 1500 N.
(b) Ratio force to the antelepe's weight = 3.40
Explanation:
Force : This can be defined as the product of mass and the distance moved by a body. Its S.I unit is Newton. It can be represented mathematically as
F = Ma
Where F= force, M = mass (Kg) and a = Acceleration (m/s²)
Weight: This can be defined as the force on a body due to gravitation field. It is also measured in Newton (N). It can be represented mathematically as
W = Mg
Where W = weight of the body, M = mass of the body (Kg), g = Acceleration due to gravity.
(a)
F = Ma
Where M = 45kg,
a = unknown.
But we can look for acceleration Using one of the equation of motion,
v² = u² + 2gs
Where v= final velocity(m/s), u = initial velocity (m/s) g = 0 m/s, g = 9.8m/s² and s = height = 2.5m.
∴ v² = 2gs
v = √2gs = √(2×9.8×2.5)
v= √49 = 7m/s
With the force applied, the impala’s velocity must increase from 0 m/s to 7 m/s in 0.21 second
∴ a = (v-u)/t
a = (7-0)/0.21 = 7/0.21
a = 33.33 m/s².
F = 45 × 33.33 ≈ 1500
F = 1500 N.
(b)
Where F = Force = 1500 N
and W = Weight = Mg = 45 × 9.8 = 441 N
∴Ratio force to the antelepe's weight = F/W = 1500/441 = 3.40
Ratio force to the antelepe's weight = 3.40
The answer is going to be ∛24=(∛8)(∛3)=2∛3
