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Misha Larkins [42]
3 years ago
12

The diagram represents wavelengths of different colors of visible light that pass by in a specific time period.

Physics
2 answers:
LekaFEV [45]3 years ago
7 0
Violet is the greatest
nata0808 [166]3 years ago
4 0

Answer:

Violet

Explanation:

Hope this helps! <3

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Based on this how many Carbon<br> Atoms would be on the products <br> Side
pashok25 [27]
Please clarify the question, and add more information before I can answer that, I’d need to know the amount of carbon atoms.
8 0
3 years ago
A jet transport with a landing speed of 200 km/h reduces its speed to 60 km/h with a negative thrust R from its jet thrust rever
Amanda [17]

Answer:

257 kN.

Explanation:

So, we are given the following data or parameters or information in the following questions;

=> "A jet transport with a landing speed

= 200 km/h reduces its speed to = 60 km/h with a negative thrust R from its jet thrust reversers"

= > The distance = 425 m along the runway with constant deceleration."

=> "The total mass of the aircraft is 140 Mg with mass center at G. "

We are also give that the "aerodynamic forces on the aircraft are small and may be neglected at lower speed"

Step one: determine the acceleration;

=> Acceleration = 1/ (2 × distance along runway with constant deceleration) × { (landing speed A)^2 - (landing speed B)^2 × 1/(3.6)^2.

=> Acceleration = 1/ (2 × 425) × (200^2 - 60^2) × 1/(3.6)^2 = 3.3 m/s^2.

Thus, "the reaction N under the nose wheel B toward the end of the braking interval and prior to the application of mechanical braking" = The total mass of the aircraft × acceleration × 1.2 = 15N - (9.8 × 2.4 × 140).

= 140 × 3.3× 1.2 = 15N - (9.8 × 2.4 × 140).

= 257 kN.

4 0
3 years ago
a car initially at rest can accelerate at 7 m/s^2 how long will it take the car to reach 60 m/s and how far will it travel durin
Alex787 [66]

1. The time taken for the car to reach a velocity of 60 m/s is 8.57 s

2. The distance travelled during the time is 257.14 m

<h3>What is acceleration? </h3>

The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

1. How to determine the time

  • Initial velocity (u) = 0 m/s
  • Acceleration (a) = 7 m/s²
  • Final velocity (v) = 60 m/s
  • Time (t) =?

a = (v – u) / t

Thus,

t = (v – u) / a

t = (60 – 0) / 7

t = 8.57 s

2. How to determine the distance

  • Initial velocity (u) = 0 m/s
  • Acceleration (a) = 7 m/s²
  • Final velocity (v) = 60 m/s
  • Distance (s) = ?

v² = u² + 2as

60² = 0² + (2 × 7 × s)

3600 = 0 + 14s

3600 = 14s

Divide both sides by 14

s = 3600 / 14

s = 257.14 m

Learn more about acceleration and velocity:

brainly.com/question/491732

brainly.com/question/19466392

#SPJ1

7 0
1 year ago
This type of polarization occurs when light strikes the atoms of a material.
zloy xaker [14]

Option C i.e scattering is the correct answer.

Scattering type of Polarization occurs when light strikes the atoms of a material.

Polarization is the process of transforming unpolarized light into polarized light. There are four methods of polarisation--Transmission, Refraction, Reflaction and Scattering.

4 0
3 years ago
Read 2 more answers
A square plate of copper with 55.0 cm sides has no net charge and is placed in a region of uniform electric field of 82.0 kN/C d
Alex73 [517]

Answer

given,

Side of copper plate, L = 55 cm

Electric field, E = 82 kN/C

a) Charge density,σ = ?

  using expression of charge density

 σ = E x ε₀

ε₀ is Permittivity of free space = 8.85 x 10⁻¹² C²/Nm²

now,

 σ = 82 x 10³ x 8.85 x 10⁻¹²

 σ = 725.7 x 10⁻⁹ C/m²

 σ = 725.7 nC/m²

change density on the plates are 725.7 nC/m² and -725.7 nC/m²

b) Total change on each faces

   Q = σ  A

   Q = 725.7 x 10⁻⁹ x 0.55²

   Q = 219.52 nC

Hence, charges on the faces of the plate are 219.52 nC and -219.52 nC

7 0
3 years ago
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