Answer:
#1
<u>Since half of the numbers are even, 2, 4, 6</u>
#2
<u>Multiple of 3 are 3 and 6:</u>
- P(multiple of 3) = 2/6 = 1/3
#3
<u>The numbers ≤ 4 are: 1, 2, 3, 4</u>
#4
<u>Prime numbers are 2, 3, 5</u>
#5
<u>Numbers > 1 are 2, 3, 4, 5, 6</u>
#6
<u>A four, there is one option</u>
Answer:
Well, these simulation are based on the statistics (lognormal-distributed PE, χ²-distributed s²). If you believe that only the ‘gold-standard’ of subject-simulations are valid, we can misuse the function sampleN.scABEL.sdsims() – only for the 3- and 4-period full replicates and the partial replicate:
# define a reg_const where all scaling conditions are ‘switched off’
abe <- reg_const("USER", r_const = NA, CVswitch = Inf,
CVcap = Inf, pe_constr = FALSE)
CV <- 0.4
2x2x4 0.05 0.4 0.4 0.95 0.8 1.25 34 0.819161 0.8
Since the sample sizes obtained by all simulations match the exact method, we can be confident that it is correct. As usual with a higher number of simulations power gets closer to the exact value.
Step-by-step explanation:
Answer: 5:40 am
Step-by-step explanation:
The train reached the station at 9:15 am after having travelled for 3 hrs 35 minutes.
The time the train departed from Riya's hometown was the time it arrived in Mumbai station less the time taken to travel:
= 9:15 - 3:35
First deduct the 3 hours:
= 9:15 - 3
= 6 : 15 am
Remove the 35 minutes by first removing the 15 minutes
= 6:15 - 15
= 6:00 am
Then remove the rest of the 35 minutes which is 20 minutes:
= 6:00 - 20 minutes
= 5:40 am
Answer:
It is a same size scalene triangle as the original triangle.
Step-by-step explanation:
:)
Start by subtracting $6.95 from $13.50. Then add $5 to the answer.
$13.50 - $6.95 = $6.55
$6.55 + $5 = $11.55
$11.55 <--- your answer
Hope this helps!
