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Rama09 [41]
3 years ago
14

Rewrite the expression in the form k times y^n 3y^-4/3 x 2 times the cubed root of y

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

6y^-1

Step-by-step explanation:

I had this question on Khan Academy

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ABC underwent a sequence of rigid transformations to give ABC. Which transformations might have taken place ?
SVEN [57.7K]

Either a reflection across the origin. Or a 180° clockwise rotation.

5 0
3 years ago
What is it??????????
spayn [35]

Hey! :)

Some things to note: When you bring a exponent to the numerator, you make it negative.

When you put an exponent to another exponent, you multiply the exponents together.

(\frac{3x^2y^5}{x^6y^2} )^4\\\frac{81x^8y^{20}}{x^{24}y^8}\\81x^8x^{-24}y^{20}y^{-8}\\\frac{81y^{12}}{x^{16}}

so that is your answer, please let me know if you need more of an explanation. :)

8 0
3 years ago
A cylinder with a radius of 4 yd and a volume of 80yd (find the height)
Afina-wow [57]

Answer:

Height of the cylinder = 1.60yd

Step-by-step explanation:

Volume of a cylinder =

V = πr^2h

V - volume of cylinder

π - 3.142

r - radius of cylinder

h - height of cylinder

We are provided with

V - 80

r - 4

π - 3.142

h - ?

80 = 3.142 * 4^2 * h

80 = 50.272 * h

To find h, divide both sides by 50.272

80/50.272 = 50.272h/ 50.272

1.599 = h

h = 1.60yd

7 0
3 years ago
Read 2 more answers
If the right side of the equation dy dx = f(x, y) can be expressed as a function of the ratio y/x only, then the equation is sai
melomori [17]

Answer:

 y = x*sqrt(Cx - 1)

Step-by-step explanation:

Given:

                                  dy / dx = (x^2 + 5y^2) / 2xy

Find:

Solve the given ODE by using appropriate substitution.

Solution:

- Rewrite the given ODE:

                               dy/dx = 0.5(x/y) + 2.5(y/x)

- use substitution y = x*v(x)

                               dy/dx = v + x*dv/dx

- Combine the two equations:

                                v + x*dv/dx = 0.5*(1/v) + 2.5*v

                                x*dv/dx = 0.5*(1/v) + 1.5*v

                                x*dv/dx = (v^2 + 1) / 2v

-Separate variables:

                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

3 0
3 years ago
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