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3 years ago

Rewrite the expression in the form k times y^n 3y^-4/3 x 2 times the cubed root of y

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer:

6y^-1

Step-by-step explanation:

I had this question on Khan Academy

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Suppose you and your 4 friends (5 people) are dressing up as the 6 main characters of the first Avengers movie: Iron Man, Hulk,

Dennis_Churaev [7]

Answer:

720

Step-by-step explanation:

If every person has to choose a different character, the first person to choose a character has 6 options, the second has 5, the third has 4, the fourth has 3, and the last person has only two options. Therefore, the total number of ways you can do this if all 5 people dress up as a different character is:

$n=6*5*4*3*2\\n=720$

There are 720 ways.

5 0

3 years ago

In performing a chi-square goodness-of-fit test with multinomial probabilities, the ___________ the difference between observed

DedPeter [7]

Answer:

Step-by-step explanation:

The smaller/closer the difference between observed and expected frequencies, the higher the probability of concluding that the probabilities specified in the null hypothesis are correct concluding that the data fits that particular distribution given.

3 0

3 years ago

In a certain constituency, there are 8 500 voters and

babymother [125]

First let's find how much is 15% of 8500 voters.

To do that, we can multiply 15 by 8500 and then divide by 100.

Work: 15 x 8500 = 127500

127500/100 = 1275

Therefore 15 percent of 8500 is 1275.

Then, we subtract 1275 from 8500 to find the amount of people who did vote.

8500 - 1275 = 7,225

Thus, 7,225 people voted while 1,275 people did not.

8 0

3 years ago

Read 2 more answers

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago

Simplify. 7/8+(−2/3) divided by 5/6

Sedaia [141]

7/8+(−2/3) divided by 5/6

(7/8 - 2/3)/(5/6)
=(21/24 - 16/24) / (5/6)
= (5/24) / (5/6)
= 5/24 * 6/5
= 6/24
= 1/4

7 0

3 years ago

Read 2 more answers