Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer: -5/21.
Step-by-step explanation:
![\frac{2}{5}*[\frac{-3}{7} +(\frac{-1}{6})]=\frac{2}{5} *(-\frac{3}{7} -\frac{1}{6}) =\frac{2}{5}*(-\frac{3*6+1*7)}{7*6} )=\frac{2}{5}*(-\frac{18+7}{42})=\frac{2}{5}*(-\frac{25}{42})=-\frac{5}{21} .](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%2A%5B%5Cfrac%7B-3%7D%7B7%7D%20%2B%28%5Cfrac%7B-1%7D%7B6%7D%29%5D%3D%5Cfrac%7B2%7D%7B5%7D%20%2A%28-%5Cfrac%7B3%7D%7B7%7D%20-%5Cfrac%7B1%7D%7B6%7D%29%20%3D%5Cfrac%7B2%7D%7B5%7D%2A%28-%5Cfrac%7B3%2A6%2B1%2A7%29%7D%7B7%2A6%7D%20%20%29%3D%5Cfrac%7B2%7D%7B5%7D%2A%28-%5Cfrac%7B18%2B7%7D%7B42%7D%29%3D%5Cfrac%7B2%7D%7B5%7D%2A%28-%5Cfrac%7B25%7D%7B42%7D%29%3D-%5Cfrac%7B5%7D%7B21%7D%20.)
Good luck an' have a nice day!
<span>The y-intercept of is .
Of course, it is 3 less than , the y-intercept of .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.
is the mirror image of stretched along the y-direction.
The y-intercept, the value of for , is</span><span>which is times the y-intercept of .</span><span>Because of the negative factor/mirror-like graph, the intervals where increases are the intervals where decreases, and vice versa.
The end behavior is similarly reversed.
If then .
If then .
If then .
The same goes for the other end, as tends to .
All of the above applies equally to any function, polynomial or not, odd, even, or neither odd not even.
Of course, if polynomial functions are understood to have a non-zero degree, never happens for a polynomial function.</span><span> </span>
Given:
The figure of a triangle DEF.
To find:
The coordinate of image of given triangle after reflection over y-axis.
Solution:
The vertices of given triangle are D(1,4), E(4,3), F(2,0).
If a figure is reflected over the y-axis, then the rule of reflection is
Using this rule, we get
Therefore, the coordinates of image are D'(-1,4), E'(-4,3) and F'(-2,0).
Answer:
3a+6
Step-by-step explanation:
3a+6 = 24a+48 divided by 8 (there are 8 sides in an octagon)
covert 24a +48 inches into feet
2a+4 feet = 18 feet
subtract 4 from both sides
2a = 14
divided 2 from both sides
a = 7
covert 3a+6 inches into feet
0.25a +0,5
0.25(7)+0.5
= 2.25
verify your answer
2.25 x 8 = 18
