x is the number of adults and y is the number of children.
x + y = 12
<span>14x + 10y = 140
lets multiply the first equation by -10 and then add it to the second equation:
-10x - 10y = -120
</span>14x + 10y = <span>140
</span>-----------------------
4x + 0 = 20
x = 20/4
x = 5
then substitute in the original equation:
x + y = <span>12
</span>5 + y = <span>12
</span>y = 12 - 5
y = 7
therefore there were 5 adults and 7 children
Answer:
Use simultaneous equation for this problem
y= number of adults
x = number of children
3y + 2x = 160
y + x = 60
then we double the second equation
3y + 2x = 160
2y + 2x = 120
we cancel x by elimination
3y - 2y = 160 - 120
y = 40
Step-by-step explanation:
hope this helps
For this question the answer would be x=-3 and x=-2
