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zaharov [31]
3 years ago
9

PLEASE ANSWER THIS ASAP !!!

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

3

Step-by-step explanation:

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Keeping the properties of exponents in mind, to what power must you raise the expression 7 1/2 to get 7 as a result
zhenek [66]
For this case we have the following expression:
 7 ^ {(1/2)}

 Rewriting the expression we have:
 (7 ^ {(1/2)}) ^ x

 Where,
 x: exponent to which we must raise the expression to obtain 7 as a result.
 We have then:
 7 ^ {((1/2) x)}

 The exponent must be equal to 1:
 (1/2) x = 1

 Clearing x we have: 
 x = 2

 Substituting valres:
 7 ^ {((1/2) 2)}

7 ^ 1

7
 Answer:
 
you must raise the expression to 2
7 0
3 years ago
Beth writes a number that shows 60 parts out of 100
dangina [55]

Answer:

60/100               orrrrrrrrrrrrrrrr 6/10

Step-by-step explanation:

4 0
3 years ago
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4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
3 years ago
Graph y-4=2x and identify<br> the slope and y-intercept.
zzz [600]

Answer:

slope is 2 and y-intercept is (0, 4)

Step-by-step explanation:

7 0
3 years ago
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9 batteries cost 13 dollars.It's ratios and Rates
8090 [49]
One battery costs $1.44.

The unit rate would be
\frac{1.44}{1 battery}

To get that answer, you would have to divide 13 ÷ 9.

I'm not sure if this is what you were looking for, but if it was, I hope I helped! :-)
4 0
3 years ago
Read 2 more answers
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