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Drupady [299]
3 years ago
15

Given the nuclear equation below, this equation is an example of

Chemistry
1 answer:
netineya [11]3 years ago
4 0

Answer:

2. beta decay

Explanation:

hope it helps

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there are 1540 megawatts of wind-generated electricity produced globally every year. This amount is equivalent to how many kilow
Reptile [31]

1.54 x 10⁶kW

Explanation:

The problem here is converting from megawatts into kilowatts.

  Given 1540megawatts.

The mega- and kilo- watts are prefixes that denotes multiples of units.

  1 megawatt = 10⁶watts

  1 kilowatt = 10³watts

Now given 1540megawatts power to Kilowatt power;

   We see that :

   1000kW = 1mW

 1540mW x \frac{1000kW}{1mW} = 1.54 x 10⁶kW

learn more:

energy units brainly.com/question/4791744

#learnwithBrainly

4 0
3 years ago
A diver has 3,400 J of gravitational potential energy after climbing
Zanzabum

Answer:

57.8kg

Explanation:

Potential energy is given by:

U =mgh

Where U is potential energy, m is mass, g is acceleration due to gravity, and h is height. Using this equation:

3400=m(9.8)(6)\\3400=58.8m\\m=57.8kg

3 0
3 years ago
When a chemical reaction is run in aqueous solution inside a calorimeter, the temperature change of the water (and Ccal) can be
Yakvenalex [24]

Answer:

The total change in enthalpy for the reaction is - 81533.6 J/mol

Explanation:

Given the data in the question;

Reaction;

HCl + NaOH → NaCl + H₂O

Where initial temperature is 21.2 °C and final temperature is 28.0 °C. Ccal is 1234.28 J

Moles of NaOH  = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol

Moles of HCl = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol

so, 0.0500 moles of H₂O produced

Volume of solution = 50.mL  +  50.mL  = 100.0 mL

Mass of solution m = volume × density = 100.0mL × 1.0 g/mL = 100 g

now ,

Heat energy of Solution q= (mass × specific heat capacity × temp Δ) + Cal

we know that; The specific heat of water(H₂O) is 4.18 J/g°C.

so we substitute

q_soln = (100g × 4.18 × ( 28.0 °C - 21.2 °C) ) + 1234.28

q_soln = 2842.4 + 1234.28

q_soln = 4076.68 J

Enthalpy change for the neutralization is ΔH_{neutralization}

ΔH_{neutralization} = -q_soln / mole of water produced

so we substitute

ΔH_{neutralization} = -( 4076.68 J ) / 0.0500 mol  

ΔH_{neutralization} = - 81533.6 J/mol

Therefore, the total change in enthalpy for the reaction is - 81533.6 J/mol

6 0
3 years ago
What is the empirical formula for P4O10?
Sphinxa [80]

Answer: P2O5

Explanation: You divide both subscripts by 2 to get the empirical formula.

8 0
3 years ago
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What is the hybridization of the central atom in becl2?
Anuta_ua [19.1K]
Its hybridization would be sp because Be only has 2 covalent bonds with Cl
4 0
3 years ago
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