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(i) Volume of point Naon to reach equivalence. = 24.0mL
(ii) volume of Naon used to reach 50% T = 12.0mL
(iii) PKA of an unknown acid = 4.8
(iv) moles of acid reacted = moles of NaOH
man/molar mass = 0.269g/MW = Molarity x volume
0.269g/MW = 0.09560 mol/K x 24. 0×/K
MW = 0.269g/0.09560 mol x 24.0x
MW = 117.24g mol-1
(v) In matching the given table of molar masses. with obtained man matches with that, we get that it of hexanoic acid.
<u>unknown acid = hexanoic acid</u>
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Titration is used to determine the amount of a substance present by reacting it with a known amount of another substance. For example, the molar mass of an acid can be found by titrating it with a base solution of known concentration. Your unknown solid is an acid. This is dissolved in water and phenolphthalein indicator is added and titrated to the endpoint with standard NaOH solution. Unknown acids are monobasic. There is only one acidic hydrogen per molecule.
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