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Westkost [7]
3 years ago
11

Prove that; tan20+4sin20= square root of3

Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × <u>2 Sin(20).Cos(20)</u>/ Cos(20) =

Sin( 20 ) + 2 × <u>Sin( 40 )</u><u> </u>/ Cos( 20 ) =

Sin( 20 ) + 2<em>Sin( 40 )</em> / Cos( 20 ) =

Sin( 20 ) + 2<em>C</em><em>o</em><em>s</em><em>(</em><em> </em><em>5</em><em>0</em><em> </em><em>)</em><em> </em>/ Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + <em>2Cos ( 20 + 30 ) </em>/ Cos( 20 ) =

Sin( 20 ) + <em>√</em><em>3</em><em> </em><em>C</em><em>o</em><em>s</em><em>(</em><em>2</em><em>0</em><em>)</em><em> </em><em>-</em><em> </em><em>S</em><em>i</em><em>n</em><em>(</em><em>2</em><em>0</em><em>)</em><em> </em>/ Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

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