I would tell him to increase the amount of voltage so the cows would feel the electricity more than what they used to.this is what i think
Answer:
The electric field is ![E = 2.2625 *10^{6} \ N/C](https://tex.z-dn.net/?f=E%20%20%3D%20%202.2625%20%2A10%5E%7B6%7D%20%5C%20%20N%2FC)
Explanation:
From the question we are told that
The radius of the inner sphere is ![r_1 = 0.008\ m](https://tex.z-dn.net/?f=r_1%20%3D%20%200.008%5C%20m)
The radius of the outer sphere is ![r _2 = 0.018 \ m](https://tex.z-dn.net/?f=r%20_2%20%20%3D%20%200.018%20%5C%20m)
The charge on the inner sphere is ![q_1 = 3.62 *10^{-8} \ C](https://tex.z-dn.net/?f=q_1%20%3D%20%203.62%20%2A10%5E%7B-8%7D%20%5C%20C)
The charge on the outer sphere is ![q_2 = 1.62 *10^{-8} \ C](https://tex.z-dn.net/?f=q_2%20%3D%201.62%20%2A10%5E%7B-8%7D%20%5C%20C)
The position from the origin is ![d = 0.012 \ m](https://tex.z-dn.net/?f=d%20%3D%20%200.012%20%5C%20m)
Generally the electric field is mathematically represented as
![E = \frac{k (q_1 )}{ r^2}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bk%20%28q_1%20%29%7D%7B%20r%5E2%7D)
The reason for using
for the calculation is due to the fact that the position considered is greater than the
but less than ![r_2](https://tex.z-dn.net/?f=r_2)
Here k is the Coulomb constant with value ![k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A{-2}](https://tex.z-dn.net/?f=k%20%3D%209%2A10%5E%7B9%7D%20%5C%20kg%5Ccdot%20m%5E3%5Ccdot%20s%5E%7B-4%7D%20%5Ccdot%20A%7B-2%7D)
So
![E = \frac{9*10^9 (3.62 *10^{-8}}{0.012^2}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B9%2A10%5E9%20%283.62%20%20%2A10%5E%7B-8%7D%7D%7B0.012%5E2%7D)
![E = 2.2625 *10^{6} \ N/C](https://tex.z-dn.net/?f=E%20%20%3D%20%202.2625%20%2A10%5E%7B6%7D%20%5C%20%20N%2FC)
Since the man and the walkway has velocity (which is a vector) moving in the same direction, who would add the velocities together.
That means the relative velocity would be 2 m/s to the East
If you picture it in your mind, imagine walking down an escalator, you feel like you're moving faster than you really are.
In a different example, if the man was moving 0.9 m/s to the West, they are moving in opposite directions, which means you would subtract the 2 velocities.
If the floor is truly frictionless, then ANY force, no matter how small, applied for
ANY time, no matter how short, will set the block in motion. The force can then
be taken away, because on a frictionless surface, NO force is required in order
to keep the block moving.
The work done is equal to the kinetic energy you want the block to have. That
can be as much or as little as you feel like giving it.
Answer:
373 K
Explanation:
To convert from °C to kelvin, you add the value to 273
Therefore,
100°C = (100+273)K
= 373K