<span>18/37 if you're in Europe, 9/19 if you're in America, assuming the wheel isn't rigged.
If the roulette wheel is a fair wheel, the odds on any given spin of the wheel is unaffected by any previous spins of the wheel. So no matter how many times the wheel has consecutively come up red, the next spin can still come up red, black, or green based upon the number of each color is present on the wheel. The difference between the odds for Europe vs America has to do with a quirk about roulette. In Europe, the roulette wheel has 37 slots, 18 red, 18 black, and 1 green. In America, the roulette wheel has 38 slots, 18 red, 18 black, and 2 green.
Although in this case, I'd be wary about assuming that the wheel isn't rigged. The odds of 270 consecutive red on a fair wheel is only 1 in 3.09663x10^84 in Europe, or 1 in 4.14949x10^87 in America.</span>
Answer:
h = 5.318 m
Step-by-step explanation:
6.5/11 = h/9
0.5909 = h/9
h = 5.318
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
Answer:
64 adult tickets were sold
Step-by-step explanation:
Let a = adult tickets sold
c = child tickets sold
a+c = 90 since there were 90 tickets sold
12a+7c = 950 since the amount of money collect is 950
c = 90-a
Substitute this into the second equation
12a +7( 90-a) = 950
Distribute
12a + 630-7a = 950
Combine like terms
5a +630 = 950
Subtract 630 from each side
5a = 950-630
5a = 320
Divide by 5
5a/5 = 320/5
a =64
64 adult tickets were sold
