The van can carry 6 students and bus can carry 21 students.
Step-by-step explanation:
Given,
High School A: 12 vans and 11 buses with 303 students
High School B: 6 vans and 7 buses with 183 students
To find the number of students that a van and a bus can carry.
Let us take,
The van can carry x students and the bus can carry y students.
According to the problem,
12x+11y = 303 ------- (1)
6x+7y = 183 ------- (2)
Multiplying 2 with (2) and subtract (1) and (2) we get,
(12x+11y) - 2(6x+7y) = 303-2(183)
or, 12x+11y-12x-14y = 303-366
or, -3y = -63
or, y = 21
From (2) we get,
6x+7(21) = 183
or, 6x = 183-147
or, 6x = 36
or, x = 6
Hence,
The van can carry 6 students and bus can carry 21 students.
I believe the question is:
What is the solution to 5x + 1 +9 - 3
In this case, we solve for X.
5x + 1 + 9 - 3
5x + 10 - 3
5x + 7
5x = -7
x = -7/5
Unfortunately, It is not one of the answer choices it looks like.
Maybe you should reword your question but hopefully this is correct.
If you meant to say 5x+1 + 9 < 3 --> 5x + 10 < 3 --> 5x < -7 --> x < -7/5
To simplify<span> a </span>fraction<span>, both the numerator and denominator must be divided by the </span>same number<span>. This method is also called canceling </span>down<span> or reducing the </span>fraction<span>. </span>
Answer:
Step-by-step explanation:
Let the function be:
f(x, y) = 2(y^2) - x^2 = 8
Since the shortest distance is basically a straight line from point (3, 0) to
f(3, y).
2y^2 - 3^2 = 8
2y^2 = 17
y = sqrt(17/2)
So the nearest point on the planes course to the point (3,0) is (3, sqrt(17/2))
Now lets use the distance formula:
x1 = 3
y1 = 0
x2 = 3
y2 = sqrt(17/2)
So m in this case is just 17/2 and the square root of m is sqrt(17/2) = 2.91547594742
Answer:
Step-by-step explanation:
It’s not c