Can someone help with numbers 1 and 2 for both of them tell me the answer and how you get it
2 answers:
Answer:
a = 20, b = 8
Step-by-step explanation:
Using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
(1)
a² + 15² = 25²
a² + 225 = 625 ( subtract 225 from both sides )
a² = 400 ( take the square root of both sides )
a = = 20
(2)
b² + 6² = 10²
b² + 36 = 100 ( subtract 36 from both sides )
b² = 64 ( take the square root of both sides )
b = = 8
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Answer:
Vertex: (-4, -1)
Y-intercept: (0, 15)
Step-by-step explanation:
Given the quaratic function, h(x) = x² + 8x + 15:
In order to determine the vertex of the given function, we can use the formula, .
In the quadratic function, h(x) = x² + 8x + 15, where:
a = 1, b = 8, and c = 15:
Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.
x = -4
Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:
h(x) = x² + 8x + 15
h(-4) = (-4)² + 8(-4) + 15
h(-4) = 16 - 32 + 15
h(-4) = -1
Therefore, the vertex of the given function is (-4, -1).
<h3>Solve for the Y-intercept:</h3>The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:
h(x) = x² + 8x + 15
h(0) = (0)² + 8(0) + 15
h(0) = 0 + 0 + 15
h(0) = 15
Therefore, the y-intercept of the quadratic function is (0, 15).
