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3 years ago

What function matches the table

Mathematics

1 answer:

IceJOKER [234]3 years ago

5 0

D, 12 is the initial number-y intercept while each time it increases up 5 over 1 for a slope of 5

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Answer the following questions.

schepotkina [342]

<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind \: of\:junk} & \bf{Price \: of \: 1 \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \: Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: newspaper = Rs.5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.20 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}$

$\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}}}}$

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

$\rule{200}{1.5}$

2. What is the cost of 5 kg Iron?

$\quad{\longrightarrow{\sf{Cost\: of \: 1 \: kg \: iron = Rs.10}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 5 \: kg \: iron = Rs.10 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 5 \: kg \: iron = Rs.50}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: iron = Rs.50}}}}}$

<u>∴ The cost of 5 kg iron is Rs.50.</u>

$\rule{200}{1.5}$

3. What is the cost of 9 kg Plastic?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: plastic = Rs.8}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.8 \times 9}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.72}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \: 9 \: kg \: plastic = Rs.72}}}}}$

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

$\rule{200}{1.5}$

4. What is the cost of 7 kg Brass?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: brass = Rs.50}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 7 \: kg \: brass = Rs.50 \times 7}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 7 \: kg \: brass = Rs.350}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: brass = Rs.350}}}}}$

<u>∴ The cost of 7kg brass is Rs.350.</u>

$\underline{\rule{200pt}{2pt}}$

7 0

2 years ago

a class has 27 students.15 are boys the rest are girls. what is the ratio of girls to total students?

liraira [26]

15 boys to 12 gurls, 15:12

6 0

3 years ago

Which is the graph of g(x) = [X +3]?<br> 32-1.

raketka [301]

Answer:

44. f(x) = x/(x2 * 1) 1 45. f(x) = 3x15 * 5x3 + 3 46. f(x) = x + — x 47. (a) Use a graphing calculator or computer to graph the function f(x) = x4 * 3x3 * 6x2 + 7x + 30 in the viewing 1 l3. F(x)=(%x)5 ... t 3|. '=* 32. = > 1) y (t*1)2 t2+2 r=\/Y 33. '= 34.

Step-by-step explanation:

4 0

2 years ago

Rhianna is buying a car for $14,390. She has a $1000 trade-in allowance and will make a $1500 down payment. She will finance the

antoniya [11.8K]

Answer:

(a)

Original price for the Car Rhianna buy = $14,390.

Trade in allowance she has =$1000

So, the reduced price= $14,390-$1,000=$13,390.

Now, she make a $1500 down payment initially, so the remaining amount she pay using Auto-Loan is, $13,390-$1500=$11,890

Therefore, $11,890 money will she borrow in an auto loan.

(b)

To find the monthly(M) auto payment be:

Since the monthly auto payment in 4 year with 2.6% APR(Annual percentage rate)

Now, Monthly Auto payment(M) be :

P=$11,890, Monthly Car payment per $1000 borrowed at 2.6% for 48 months = $21.958

∴ $M=$11,890\cdot \frac{21.958}{1000}$

On solving we get, M=$261.082

Therefore, $261.082 will be her monthly auto payment.

(c)

Total amount of interest(A) she will pay ,

A=total payment in 4 years-total loan amount= $(\$261.082\cdot 48)-11,890$

=$12,531.936-$11,890=$641.936

So, the total amount of interest she will pay is, $641.936

(d)

Rhianna total payment for the car = total payment in 4 years+Down payment= $(261.082\cdot 48)+$1500$ =$12531.936+$1500=$14,031.936

(e)

∵ Rhianna is 22 years female :

From the given Data in the picture:

Rating factor= 1.2

Liability insurance 50/100/25 , Bodily injury 50/100

Premium= $310 and Property damage 25 : Premium $175

Collision insurance=$500 deductible: Premium $148

Comprehensive insurance= $500 deductible : Premium $85

Her total annual premium $= 1.2\cdot (\$310+\$175+\$148+\$85) = \$861.60$

8 0

2 years ago

If f(x) = x^2 - 2x and g(x) = 6x + 4, for what value of x does (f + g)(x) = 0?

larisa86 [58]

Answer:

x = -2

Step-by-step explanation:

$f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2$

6 0

2 years ago

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