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3 years ago

9

Martin used a cube with sides numbered 1 - 6 in a probability experiment. The table shows the results of 30 trials of the experi

ment.
Possible Outcome
1 2 3 4 5 6
Number of Outcomes During the Experiment 4 3 6 7 5 5
Martin uses the results to determine the experimental and theoretical probabilities of tossing the cube once with the outcome being an odd
number.

1 answer:

Rufina [12.5K]3 years ago

7 0

Answer:

Theoretically, all of the sides have an equal chance of getting rolled.

Step-by-step explanation:

This trial is a little small, so the results do not show the full probabilities.

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PLEASE HELP!!!!!!!!! WILL MARK BRAINLIEST!!

svet-max [94.6K]

Answer:

b=-0.0019a + 215

at 2500 ft, b=210.25 degrees F

Step-by-step explanation:

First find the slope. a=altitude, b = temperature

slope is b2-b1 / a2-a1

points are (8200, 199.42) and (4700, 206.07)

(206.07 - 199.42) / (4700-8200)

= 6.65/ -3500

= - 0.0019

we have b = -0.0019a + intercept

plug in a point to find intercept

199.42 = -0.0019*8200 + intercept

intercept = 199.42 + 15.58 = 215

b=-0.0019a + 215

at a=2500 ft, substitute into equation

b= -0.0019*2500 + 215

= -4.75 + 215

= 210.25 degrees F

please give thanks by clicking heart button :)

4 0

2 years ago

Help plz thankssssss

Monica [59]

The formula for slope is y2-y1 divided by x2-x1

7 0

3 years ago

How can you get the square side area??

emmainna [20.7K]

Buy what he said to multiple or divide length times width

5 0

2 years ago

Help with #9 pleaseeee

Molodets [167]

Answer:

9' - 1.29"

Step-by-step explanation:

Total rise = 5' - 2"

Total run = 7' - 6"

1' = 12" = 1 feet = 12 inches

5' = 5 * 12 = 60"

3' = 7 * 12 = 84"

Total rise = 60" + 72" = 62"

Total run = 84" + 6" = 90"

Length of stringer = hypotenus

Hypotenus = √(total rise² + total run²)

Hypotenus = √(62² + 90²)

Hypotenus = 109.28860"

Convwrting back to feet and inches

= 9' - 1.29"

3 0

3 years ago

A graphing calculator is recommended. A function is given. g(x) = x4 − 5x3 − 14x2 (a) Find all the local maximum and minimum val

Taya2010 [7]

Answer:

The local maximum and minimum values are:

Local maximum

$g(0) = 0$

Local minima

$g(5.118) = -350.90$

$g(-1.368) = -9.90$

Step-by-step explanation:

Let be $g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}$ . The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

$g(x) = x^{2}\cdot (x^{2}-5\cdot x -14)$

Then, first and second derivatives of the function are, respectively:

First derivative

$g'(x) = 2\cdot x \cdot (x^{2}-5\cdot x -14) + x^{2}\cdot (2\cdot x -5)$

$g'(x) = 2\cdot x^{3}-10\cdot x^{2}-28\cdot x +2\cdot x^{3}-5\cdot x^{2}$

$g'(x) = 4\cdot x^{3}-15\cdot x^{2}-28\cdot x$

$g'(x) = x\cdot (4\cdot x^{2}-15\cdot x -28)$

Second derivative

$g''(x) = 12\cdot x^{2}-30\cdot x -28$

Now, let equalize the first derivative to solve and solve the resulting equation:

$x\cdot (4\cdot x^{2}-15\cdot x -28) = 0$

The second-order polynomial is now transform into a product of binomials with the help of factorization methods or by General Quadratic Formula. That is:

$x\cdot (x-5.118)\cdot (x+1.368) = 0$

The critical points are 0, 5.118 and -1.368.

Each critical point is evaluated at the second derivative expression:

x = 0

$g''(0) = 12\cdot (0)^{2}-30\cdot (0) -28$

$g''(0) = -28$

This value leads to a local maximum.

x = 5.118

$g''(5.118) = 12\cdot (5.118)^{2}-30\cdot (5.118) -28$

$g''(5.118) = 132.787$

This value leads to a local minimum.

x = -1.368

$g''(-1.368) = 12\cdot (-1.368)^{2}-30\cdot (-1.368) -28$

$g''(-1.368) = 35.497$

This value leads to a local minimum.

Therefore, the local maximum and minimum values are:

Local maximum

$g(0) = (0)^{4}-5\cdot (0)^{3}-14\cdot (0)^{2}$

$g(0) = 0$

Local minima

$g(5.118) = (5.118)^{4}-5\cdot (5.118)^{3}-14\cdot (5.118)^{2}$

$g(5.118) = -350.90$

$g(-1.368) = (-1.368)^{4}-5\cdot (-1.368)^{3}-14\cdot (-1.368)^{2}$

$g(-1.368) = -9.90$

7 0

3 years ago