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Llana [10]
3 years ago
8

Help me I’m struggling with this one

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

Eukarya

Explanation:

It's larger than a prokaryotic cell and it has a nucleus.

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Lunna [17]

Answer: they like deep water

Explanation: they do

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List 3 natural resources (non-living) found in the “glorious place”
victus00 [196]

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уфукингнегроитукиурепоинты

Explanation:

6 0
3 years ago
Write your question here (Keep it simple and clear to get the best answer) calculate the atomic weight of a metal when 125ml of
lana [24]

Answer:

The answer to your question is 24.32 g

Explanation:

Data

Atomic weight = ?

HCl volume = 125 ml

Molarity = 0.2

mass of metal = 0.304 g

Balanced chemical equation

                       M + 2HCl   ⇒  MCl₂  +  H₂

Process

1.- Calculate the moles of HCl

Molarity = moles / volume (L)

- Solve for moles

  moles = Molarity  x volume

  moles = 0.2 x 0.125

             = 0.025

2.- Calculate the moles of the Metal

                1 mol of M ----------------- 2 moles of HCl

                x                ----------------- 0.025 moles of HCl

                x = (0.025 x 1) / 2

                x = 0.0125 moles of HCl

3.- Calculate the atomic weight of the metal

                atomic weight ---------------- 1 mol

               0.304 g             ---------------0.0125 moles

               Atomic weight = (1 x 0.304) / 0.0125

               Atomic weight = 24.32 g    

             

7 0
3 years ago
Read 2 more answers
Suppose you want to prepare a buffer with a pH of 4.59 using formic acid. What ratio of [sodium formate]/[formic acid) do you ne
katrin [286]

Answer:

7.08

Explanation:

To solve this problem we'll use the <em>Henderson-Hasselbach equation</em>:

  • pH = pka + log\frac{[A^-]}{[HA]}

Where \frac{[A^-]}{[HA]} is the ratio of [sodium formate]/[formic acid] and pka is equal to -log(Ka), meaning that:

  • pka = -log (1.8x10⁻⁴) = 3.74

We<u> input the data</u>:

  • 4.59 = 3.74 + log\frac{[A^-]}{[HA]}

And<u> solve for </u>\frac{[A^-]}{[HA]}:

  • 0.85 = log\frac{[A^-]}{[HA]}
  • 10^{(0.85)}=\frac{[A^-]}{[HA]}
  • \frac{[A^-]}{[HA]} = 7.08
3 0
3 years ago
What will the presence of H+ ions in a solution cause?
vodka [1.7K]
The H+ will react with Magnesium to release hydrogen Gas under the equation Mg + 2H+ --> Mg(2+) + H2(g)

Hope this Helps! :)
8 0
3 years ago
Read 2 more answers
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