Do anyone know the answer please

Use the periodic table to match each of the following element symbols to its name, atomic mass, or atomic number

uysha [10]

Answer:

Explanation:

From the periodic table, the element designated as Sn is tin. Sn is derieved from a latin name of the metal called Stanum

Selenium Se is a group 6 element. It belongs to the same group with oxygen, sulfur and tellurium. This substance has an atomic weight of 78.96g/mol

Oxygen is a group 6 element with an atomic mass of 16. The atomic mass is the number of protons in the nucleus of this atom.

5 0

3 years ago

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What is the approximate bond angle around the central carbon atom in acrolein?

Soloha48 [4]

Answer:

The approximate bond angle around the central carbon atom in acrolein is 120°.

Explanation:

The structure of acrolein is shown in the attachment. From the structure, we can deduce that the central carbon atom is in an sp2 hybridization (Atoms with a double bond hybridize in an sp2 fashion).

Atoms with sp2 hybridization have trigonal planar geometry, in this kind of hybridization, bonds are oriented the farthest away possible from each other, to minimize overlapping and the angle that allows that is 120°.

7 0

3 years ago

Convert 22 grams of copper Il chloride (Cucl2) to moles. <br>with work please

Fittoniya [83]

Hope this helps!

https://youtu.be/MT5tKijKZwQ

5 0

2 years ago

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If you have 6.25g of O2, how many moles of H2O are produced?

denis23 [38]

Answer:

0.4 moles of water produced by 6.25 g of oxygen.

Explanation:

Given data:

Mass of oxygen = 6.25 g

Moles of water produced = ?

Solution:

Chemical equation;

2H₂ + O₂ → 2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 6.35 g/ 32 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of oxygen with water:

O₂ : H₂O

1 : 2

0.2 : 2×0.2 = 0.4 mol

0.4 moles of water produced by 6.25 g of oxygen.

8 0

3 years ago

The average lung capacity of a human is 6.0L.

Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

(c) 8.77 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol$

(b)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol$

(c)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol$

8 0

3 years ago