Answer:
b. 17,190
Explanation:
Using the formula for C-14 dating,

where Present Value N =1/8 of Parent Sample
Initial Value,
=1
Half Life,
=5730 years

=17,190
Therefore the fossil is about 17190 years old.
a.) Asp and Lys
Asp will elute first from the column because it has less positively charged functional groups than Lys.
b.) Arg and Met
Met will elute first from the column because it has less positively charged functional groups than Lys.
c.) Glu and Val
Glu will elute first from the column because it has more negativity functional groups than Lys and will be not be much retained by the -SO₃⁻ groups from the ion-exchange coloumn.
d.) Gly and Val
Gly will elute first from the column because Lys have a longer alkyl chain which will be attracted by the strongly hydrophobic backbone for the resin.
e.) Ser and Ala
Ser will be eluted first from the column because Ala alkyl chain will be more attracted by the strongly hydrophobic backbone for the resin. Ser have an -OH group which will decrease the hydrophobicity of the alkyl chain and will not be so much retained on the column.
The concentration of the sodium hydroxide solution in mol/l is 0.176 M.
Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.
Given
V =25 ml = 0.025 L
M = 0.1
C₁ = 0.1
V₁ = 21.50 = 0.022 L
C₂ = ?
V₂ = 25 ml = 0.025 L
C₁V₁ = C₂V₂
C₂ = C₁V₁ / V₂
= 0.1 * 0.022 * 2 / 0.025
= 0.176 M
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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Answer:
about 0.9 mol
Explanation:
there are 22.990 g/mol of Na
20.7/22.99 = 0.900391 mol
about 0.9 mol
If 0.25mg of atropine is in 1mL
so
0.50mg of atropine is in x