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3 years ago

Which adaptation helps a tapeworm attach itself to the intestines of its host?

Chemistry

2 answers:

Inessa05 [86]3 years ago

8 0

Answer:

what the person above me said : )

Explanation:

lubasha [3.4K]3 years ago

4 0

Answer:

B) hooks and suck- ers

Explanation:

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If a sample has 25% parent and 75% daughter, how many halflifes have gone by?

Anit [1.1K]

Answer:

Two half lives.

Explanation:

It is known that the decay of isotopes and radioactive material obeys first order kinetics.

Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

That means for a sample 100% to decay to 50 % it will take one half-life, and to decay the remaining 50% to 25% it will take another half-life.

So, for a sample has 25% parent and 75% daughter it will have two half-lives.

6 0

3 years ago

A solution with a pH level of 7.0 would be considered as an Basic, Acidic, or neutral

ASHA 777 [7]

Answer:

Neutral.

Explanation:

A solution with 7 on the pH scale would be neutral.

4 0

3 years ago

Read 2 more answers

an astronaut on the moon throws a ball at a velocity of 4.1 m/s straight up. assuming the gravity on the moon is 1/6 that of ear

Aleonysh [2.5K]

Answer:

(1/2)(1.62) t^2 = 1.4

That will give you the time, t

Explanation:

hope this helps(✿◡‿◡)

5 0

3 years ago

A student measures the absorbance of a sample of red dye #3 using a spectrophotometer. If the absorbance is measured as 0.468, w

Gre4nikov [31]

Answer:

5.88 μM is the concentration of red dye in the sample.

Explanation:

Absorbance is defined s capacity of a substance to absorb a light of a specified wavelength.It is calculated by using Beer-Lambert Law:

$A=\epsilon lc$

A = absorbance

$\epsilon$ = Molar absorptivity

c = concentration

l = Length of the solution through which light passes

Given, A = 0.468, l = d = 1.00 cm,c = ?

$\epsilon =7.96\times 10^4 M^{-1} cm^{-1}$

$A=\epsilon lc$

$0.468=7.96\times 10^4 M^{-1} cm^{-1}\times 1.00 cm\times c$

$c=5.8793\times 10^{-6} mol/L=5.8793 mol/(\mu L)\approx 5.88mol/(\mu L)$

( $1 L= 1,000,000 \mu L$ )

5.88 μM is the concentration of red dye in the sample.

5 0

3 years ago

True or False

Alexxandr [17]

Answer:

Its 26. True

27 . False

Explanation:

hope it helps !

mark me brainliest :))

8 0

3 years ago