Question

Whats the original slope of y-7/12=5/8(x+9)

Answer 1

1) Find the first derivative of f(x). 2) Plug x value of the indicated point into f '(x) to find the slope at x. 3) Plug x value into f(x) to find the y coordinate of the tangent point. 4) Combine the slope from step 2 and point from step 3 using the point-slope formula to find the equation for the tangent line.

y - 7/12 = 5/8(x + 9)

y - 7/12 = 5/8x + 45/8

  +7/12               +7/12

Original Slope is y = 5/8x + 149/24

Answer 2

Answer:

m = 5/8

Step-by-step explanation:

y-7/12=5/8(x+9) represents a linear equation whose slope we want to determine.

Clear this y-7/12=5/8(x+9) of fractions by finding the LCD (it is 72) and multiplying each term by it:

72[y - 7/12 = (5/8)(x+9)

We obtain 72y - 42 = 45(x+9).

Perform the indicated mult.:  72y - 42 = 45x + 405.

Solving for y, we get 72y = 45x + 405 + 42, or 72y = 45x + 447.

Dividing boh sides by 72 to isolate y, we get y = (45/72)x + 447/72.

The slope of this straight line is 45/72, which can be reduced to m = 5/8.