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SVEN [57.7K]
3 years ago
12

Can sum one with chegg or course hero help me!!

Mathematics
2 answers:
IceJOKER [234]3 years ago
7 0

Answer:

61 / 81 (fraction)

​​

IrinaVladis [17]3 years ago
3 0
He got it right I think
You might be interested in
Lim <br> x → 1 <br> ln(x)/<br> sin(7πx)
mote1985 [20]
\displaystyle\lim_{x\to1}\frac{\ln x}{\sin7\pi x}

Note that both the numerator and denominator approach 0 as x\to1, so we can try using L'Hopital's rule.

\displaystyle\lim_{x\to1}\frac{\lnx }{\sin7\pi x}=\lim_{x\to1}\frac{\frac1x}{7\pi\cos7\pi x}=\lim_{x\to1}\frac1{7\pi x\cos7\pi x}

The denominator is nonzero at x=1, so the limit is equivalent to

\displaystyle\frac1{\lim\limits_{x\to1}7\pi x\cos7\pi x}=\frac1{7\pi\cos7\pi}=-\frac1{7\pi}
7 0
3 years ago
Simplify n^6 × n^5 × n^4 ÷ n^2 ÷ n<br>PLEASE ANSWER ASAPPP!!! Will get BRAINLIEST****​
babymother [125]

Answer:

n¹³

Step-by-step explanation:

Division and multiplication have the same priority in pemdas, so you can solve this by dividing/multiplying from left to right.

Also remember that when dividing exponents of the same base, you subtract them, and when multiplying, you add them.

n⁶· n⁵ · n⁴ ÷ n³ · n² ÷ n

= (n⁶· n⁵) · n⁴ ÷ n³ · n² ÷ n

= (n¹¹ · n⁴) ÷ n³ · n² ÷ n

= (n¹⁵ ÷ n³) · n² ÷ n

= (n¹² · n²) ÷ n

= n¹⁴ ÷ n

= n¹³

Ultimately you just have to calculate

6 + 5 + 4 - 3 + 2 - 1 = 13

6 0
3 years ago
in the morning , Emily studied 40 minutes for an exam. Later that evening, Emily studied for x more minutes. write an equation t
julia-pushkina [17]

Answer:

40 + x = y

Just use the variables given to make an equation.

3 0
4 years ago
Read 2 more answers
Collin ordered a set of yellow and brown pins. He received 400 pins in all. 340 of the pins were yellow. What percentage of the
cupoosta [38]
The yellow pins show as 85% of the total number of pins that Collin ordered
6 0
4 years ago
The goal of a nutritional study was to compare the caloric intake of adolescents living in rural areas of the US with the calori
stiks02 [169]

Answer:

To give more clarity to the question, lets examine the attached back-to-back stem plot.

A)

Having examined the stem plot, we can using quick calculations, summarize that:

The mean (40.45 cal/kg) and median (41 cal/kg) daily caloric intake of ninth-grade students in the rural school is higher than the corresponding measures of center, mean (32.6 cal/kg) and median (32 cal/kg), for ninth-graders in the urban school.

The median and the mean for the students in the 9th grade in the urban school is lower than that of those of their contemporaries in the rural school. The respective medians and means are stated below:

Urban 9th Grade Students

Median = 32 cal/kg

Mean = 36 cal/kg

Rural 9th Grade Students

Median = 41 cal/kg

Mean = 41 cal/kg

Please note that all figures above have been approximated to the nearest whole number.

B)

It is unreasonable to generalize the findings of this study to all rural and urban 9th-grade students in the United States because the sample is too small compared to the target population size.

To allow for generalization, they would have to collect and analyze more samples say from every state within America.

Cheers!

5 0
4 years ago
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