Answer: $25 spent
Step-by-step explanation: the boy spent $15/total.
15/total=3/8
Divide by common factor: $15/3=$5 (1/8 total money
$5x8=$40
$40-$15=$25 spent
Answer:
Cost of a single Mucho beef burrito: 
Cost of a double Mucho beef burrito: 
Step-by-step explanation:
<h3>
The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>
Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.
Set a system of equations:

To solve this system you can apply the Substitution Method:
1. Substitute the second equation into the first equation and solve for "y":

2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":

63 students. To solve, you first ned to determine the total cost for each student by adding 300 and 5, which equals $305. You then need to see how many times $305 will go into $19215, which shows how many students went. $19215 divided by $305 equals 65.
Step-by-step explanation:
We find the stationary point of (20 + 2x)(1200 - 60x),
where x is the unit rate of increase/decrease.
d/dx [(20 + 2x)(1200 - 60x)]
= d/dx (-120x² + 1200x + 24000)
= -240x + 1200.
When d/dx [(20 + 2x)(1200 - 60x)] = 0,
We have -240x + 1200 = 0. => x = 5.
Price per shirt that maximise revenue
= $20 + $2x = $20 + $2(5) = $30.
Maximum revenue
= (20 + 2(5))(1200 - 60(5))
= $30 * 900 = $27,000.