Did I get this correct? If not please help me!!!

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample % of U.S. public high school students who were obese = 15%

n = sample of U.S. public high school students = 300

p = population percentage of all U.S. public high school students

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ , $0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ ]

= [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0

3 years ago

God dang this is my last question will someone please like just help me on this? I literally made 3 questions and nobody is help

Art [367]

Answer:

kiki has $4.17 and jordan has $4.14 kiki has 0.03 more than jordan

Step-by-step explanation:

If you add up the numbers for kiki you get $4.17 and if you do the same for jordan with the numbers they gave you for him you get $4.14 then you just minus 4.17 and 4.14 and thats how you get 0.03.

5 0

3 years ago

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50 points pls help me pls

evablogger [386]

Answer:

1. The benefits to using a online filter app are

-Smoothing water movement in waterfalls, rivers, oceans, etc.

-Achieving a shallower depth of field in very bright light

-Reducing diffraction (which reduces sharpness) by enabling a larger -aperture

-Making moving objects less apparent or not visible (such as people or cars)

-Introducing blur to convey motion with moving subjects

2. Adobe Photoshop Express. This app provides an amazing amount of features that other apps just don't come close to the other apps I have researched. I've even done some testing on my phone and it appears to be user friendly which basically means even my grandma can use this without having a difficult time.

3. I would choose the apps filters because it has more options to choose from. The only time I would use the accessory filters would be if i'm going to something quick and simple. Since i'm more of a perfectionist I love to use the apps filters.

3 0

3 years ago

What is the Square root of 600

Elena L [17]

$\sqrt{600}=10\sqrt6\approx24.49$

8 0

4 years ago

Yasmin swims at a constant rate of 2 km/h for 2.5h how far does Yasmin swim

Scorpion4ik [409]

5 miles. For the first 2 hours she swan 4 miles, 2 each hour. Them for the .5, which is one half, you take half of 2, add it to the 4, and end up with 5.

5 0

3 years ago

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