All categories

3 years ago

12. Draw an acute scalene triangle. Describe

Mathematics

1 answer:

Alinara [238K]3 years ago

6 0

Try googling this it will give you some examples and definitions.

https://mathbitsnotebook.com/Geometry/SegmentsAnglesTriangles/SATTriangleTypes.html

You might be interested in

A text font fits 12 characters per inch. Using the same font, how many characters can be expected per yard of text?

Radda [10]

The answer is 432 characters

8 0

3 years ago

If 40x = 400, then A. x equals 100. B. x equals 10. C. I equals 4. O D. x equals 1. E. requals 0 ).

Brut [27]

Answer:

B- x= 10

Step-by-step explanation:

40x=400 -> 40 x 10= 400

8 0

3 years ago

Solve for m. 5m+72=−2m+52 Drag and drop the answer into the box.

dybincka [34]

Answer:

-20/7

Step-by-step explanation:

5m +72 = -2m + 52

5m + 2m = 52-72

7m = -20

m = -20/7

6 0

3 years ago

Read 2 more answers

A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo

SpyIntel [72]

Answer:

$R_{in}=0.2\dfrac{mL}{min}$

$C(t)=\dfrac{A(t)}{30000}$

$R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

$A(t)=300+2700e^{-\dfrac{t}{1500}},$ A(0)=3000$

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

$R_{in}=$ (concentration of chlorine in inflow)(input rate of the water)

$=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}$

Volume of the pool =30,000 Liter

$Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}$

(d) Rate at which the chlorine is leaving the pool

$R_{out}=$ (concentration of chlorine in outflow)(output rate of the water)

$= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

$\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}$

Recall that when t=0, A(t)=3000 (our initial condition)

$3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}$

3 0

3 years ago

Suppose 300 nursing students took a certification test that is worth 100 points.

Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

$Q_1 = 65$

Median = 82

$Q_3 = 88$

Maximum = 100

$Q_1$ is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below $Q_1$ and about 75% lie above $Q_1$ .

$Q_3$ is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below $Q_3$ and about 25% lie above $Q_3$

i) .About how many students scored 65 or better?

$Q_1 = 65$

Since we know that 75% lie above $Q_1$ .

So, Number of students scored 65 or better = $75\% \times 300 = \frac{75}{100} \times 300 =225$

ii)About how many students scored 88 or better?

$Q_3 = 88$

Since we know that 25% lie above $Q_3$

So, Number of students scored 88 or better = $25\% \times 300 = \frac{25}{100} \times 300 =75$

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0

3 years ago