3 years ago

Changes in the dimensions of the shape do not effect the area of the shape. True or False

2 answers:

7 0

Answer:

I’m doing the assignment and in the reading it says In this lesson, you’ll be exploring how changes in the dimensions of a figure affect its area. so I say. False

hope this helps

Step-by-step explanation:

inessss [21]3 years ago

3 0

False

Becuase I'm doing this lesson and I got it right.

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Find the length of the leg.

g100num [7]

The length of the leg is 5

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3 years ago

ABCD is a parallelogram and this figure is NOT drawn to scale.

dimulka [17.4K]

The angle does not matter. Think of it as finding the other side to a triangle. Use $a ^{2} +b^2 =c^2$

a=39 (line AB)
b=b (the leg we need to find)
c=89 (line BD)

$39^2 + b^2 = 89^2$
$1521 + b^2 = 7921$
(subtract the 1521 from both sides)
$b^2 = 6400$
(square root both sides)
$\sqrt{(b^2)} = \sqrt{6400} 
$

b = 80
AD=80

7 0

3 years ago

Read 2 more answers

Which explains how to show that x= -8/3 is a root of 9x^2+48x+64= 0 ?

Helen [10]

Step-by-step explanation:

$9 {( - \frac{8}{3}) }^{} {}^{2} + 48( - \frac{8}{3} ) + 64 \\ \\ 9( - \frac{64}{9} ) - \frac{48}{3} + 64 \\ \\ - 64 - 16 + 64 = - 16$