All categories

3 years ago

Changes in the dimensions of the shape do not effect the area of the shape. True or False

Mathematics

2 answers:

padilas [110]3 years ago

7 0

Answer:

I’m doing the assignment and in the reading it says In this lesson, you’ll be exploring how changes in the dimensions of a figure affect its area. so I say. False

hope this helps

Step-by-step explanation:

inessss [21]3 years ago

3 0

<u>False</u>

Becuase I'm doing this lesson and I got it right.

You might be interested in

Juwan is throwing a birthday party for his son. He originally ordered 3 pizzas, but he realizes that his son invited more people

grigory [225]

Answer:

Step-by-step explanation:

8 0

3 years ago

Make a table for the following equations<br> y = 2x + 4

nekit [7.7K]

In order to make a table, we sample some x values (whichever we want), and we compute the expression for those value. Each x value will yield a unique y value.

If you need this table to graph the function, you'll only need two points, since this is a line, and having two points you just need to connect them.

Here are some samples, feel free to make more if you need to:

$f(x)=2x+4\implies f(0)=2\cdot 0 + 4 = 4$

$f(x)=2x+4\implies f(1)=2\cdot 1 + 4 = 6$

$f(x)=2x+4\implies f(2)=2\cdot 2 + 4 = 8$

$f(x)=2x+4\implies f(3)=2\cdot 3 + 4 = 10$

$f(x)=2x+4\implies f(4)=2\cdot 4 + 4 = 12$

So, we have the following table

$\begin{array}{c|c}0&4\\1&6\\2&8\\3&10\\4&12\end{array}$

4 0

3 years ago

Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the varia

Anon25 [30]

Answer:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property.

Step-by-step explanation:

Given the polynomial :

80b⁴ – 32b²c³ + 48b⁴c

The Greatest Common Factor (GCF) of the coefficients:

80, 32, 48

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80

32 : 1, 2, 4, 8, 16, and 32

48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

GCF = 16

b⁴, b², b⁴

b⁴ = b * b * b * b

b² = b * b

b⁴ = b * b * b * b

GCF = b*b = b²

GCF of c³ and c

c³ = c * c * c

c = c

GCF = c

We can see that David's GCF of the coefficients are all correct

From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect

In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)

6 0

3 years ago

Read 2 more answers

Help please it is due today

Svet_ta [14]

Answer:

Jane's situation is the one which represents a porportional relationship.

Step-by-step explanation:

To verify the proportionality betwen a ratio you have to divide all the ratios and all them have to get the same constant factor.

So, if you divide the matt's ratios you aren't gonna find the same constant factor

12/1=12

20/2=10

31/2=15,5

But if you try with Jane's ones:

12/1=12

24/2=12

36/3=12

This 12 is the known constant factor, which show us that these ratios are proportional.

8 0

3 years ago

if the price of an article is without tax is ₹ 800, and the price with tax is ₹ 860 the sales tax rate is_____________

vivado [14]

9514 1404 393

Answer:

7.5%

Step-by-step explanation:

The tax as a proportion of the selling price is ...

₹(860 -800)/₹800 = 60/800 = 0.075 = 7.5%

7 0

3 years ago