Changes in the dimensions of the shape do not effect the area of the shape. True or False

Mathematics

2 answers:

padilas [110]3 years ago

7 0

Answer:

I’m doing the assignment and in the reading it says In this lesson, you’ll be exploring how changes in the dimensions of a figure affect its area. so I say. False

hope this helps

Step-by-step explanation:

inessss [21]3 years ago

3 0

False

Becuase I'm doing this lesson and I got it right.

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Simplify this expression and show all steps: 48m^7/20m^4

Ghella [55]

Answer:

(12/5)m^3

Step-by-step explanation:

It's easier for most of us to write out a fraction / ratio without the " / " symbol:

48m^7

------------

20 m^4

Separate the coefficients from the powers of m:

48 m^7

----- * -------- Now let's reduce each fraction separately:

20 m^4

48/20 = 12/5, and

(m^7) / (m^4) = m^(7-4) = m^3

... so that our final answer is (12/5)m^3.

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3 years ago

I need help please 36 points

geniusboy [140]

Using the power of zero property, we find that:

a) The simplification of the given expression is 1.

b) Since , equivalent expressions are: and .

--------------------------------

The power of zero property states that any number that is not zero elevated to zero is 1, that is:

Thus, at item a, , thus the simplification is .

At item b, equivalent expressions are found elevating non-zero numbers to 0, thus and .

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3 years ago

In your biology class, your nal grade is based on several things: a lab score, scores on two major tests, and your score on the

Mariana [72]

Complete Question

In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on the final exam. There are 100 points available for each score. However, the lab score is worth 25% of your total grade, each major test is worth 22:5%, and the final exam is worth 30%. Compute the weighted average for the following scores: 92 on the lab, 81 on the first major test, 93 on the second major test, and 85 on the final exam. (Enter your answer to one decimal place)

Answer:

The weighted average is $W = 87.65$