Answer:
95% Confidence interval: (96.06,103.94)
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 85
Sample mean, 
= 100
Sample size, n = 30
Alpha, α = 0.05
Population standard deviation, σ = 11
95% Confidence interval:
Putting the values, we get,
(96.06,103.94) is the 95% confidence interval for the population mean test score.
It would be equal to 1 7/8
Step-by-step explanation:
There are 40 DuBois students going on a field trip.
Each one pays their teacher $8.75 to cover admission to the museum and lunch.
Admission for the students is $120 and each one gets an equal amount to spend on lunch.
To Find :
How much will each DuBois student be able to spend on lunch.
Solution :
Amount they paid for admission :
\begin{gathered}P =\$ \dfrac{120}{40}\\\\P=\$3\end{gathered}P=$40120P=$3
Now, amount of money to spend on lunch is 8.75 -8.75−3 = $5.75 .
Hence, this is the required solution.
Circumference
C = pi d
C = 3.14 x 10
C = 31.4 cm
Area
A = pi r^2
A = 3.14 x 5^2
A = 78.5 cm^2
