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sveta [45]
3 years ago
8

A circuit with two or more branches for current to flow

Physics
1 answer:
Natalija [7]3 years ago
4 0

If there's any point in a circuit where the current has a choice
of which branch to take, then you have a <em>parallel circuit</em>.


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How dose nail polish burnt in water?
vazorg [7]

Answer:

The reason behind fire in water when nail polish is added is the presence of acetone which is a flammable substance. Acetone, commonly known as dimethyl ketone or 2-propanone, is a flammable chemical in nail polish. Acetone is flammable as well as poisonous when it comes contact with moisture.

Explanation:

The reason behind fire in water when nail polish is added is the presence of acetone which is a flammable substance. Acetone, commonly known as dimethyl ketone or 2-propanone, is a flammable chemical in nail polish. Acetone is flammable as well as poisonous when it comes contact with moisture.

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Does everything in a black hole contain a singularity?
Lapatulllka [165]
In the real universe, no black holes contain singularities. In general, singularities are the non-physical mathematical result of a flawed physical theory.
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What change occurs to the gravitational force of attraction between two bodies when the
Lisa [10]

Answer:

when the radius is halved, F becomes 4 times

Explanation:

<u><em>The formula is given by</em></u>

F = \frac{Gm1m2}{r^2}

<u><em>When r is halved:</em></u>

F = \frac{Gm1m2}{(1/2r)^2}

=> F = \frac{Gm1m2}{1/4 r^2}

=> F = 4(\frac{Gm1m2}{r^2} )

<u><em>This means when the radius is halved, F becomes 4 times</em></u>

4 0
3 years ago
when an object falls, eventually the force of air resistance (drag) = the force of gravity. This is called ____​
jarptica [38.1K]
Terminal velocity dkdkmfocmdpdmfpfmfl
4 0
3 years ago
Consider two points in an electric field. The potential at point 1, V1, is 33 V. The potential at point 2, V2, is 175 V. An elec
Mnenie [13.5K]

Answer:

ΔU  = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J

Explanation:

Since the electric potential at point 1 is V₁ = 33 V and the electric potential at point 2 is V₂ = 175 V, when the electron is accelerated from point 1 to point 2, there is a change in electric potential ΔV which is given by ΔV = V₂ - V₁.

Substituting the values of the variables into the equation, we have

ΔV = V₂ - V₁.

ΔV = 175 V - 33 V.

ΔV = 142 V

The change in electric potential energy ΔU = eΔV = e(V₂ - V₁) where e = electron charge = -1.602 × 10⁻¹⁹ C and ΔV = electric potential change from point 1 to point 2 = 142 V.

So, substituting the values of the variables into the equation, we have

ΔU = eΔV

ΔU = eΔV

ΔU = -1.602 × 10⁻¹⁹ C × 142 V

ΔU = -227.484 × 10⁻¹⁹ J

ΔU = -2.27484 × 10⁻²¹ J

ΔU ≅ -2.275 × 10⁻²¹ J

So, the required equation for the electric potential energy change is

ΔU  = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J

5 0
3 years ago
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