A farsighted girl has a near point at 2.0 m but has forgotten her glasses at home. The girl borrows eyeglasses that have a power
of 2.75 diopters. These are not going to make her able to view normally. With these eyeglasses, what is the new near point of the girl, assuming that she wears them extremely close to her eyes
1 answer:
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Answer:
10.77m
Explanation:
The elastic potential energy of the spring when compressed with the mass is converted to the kinetic energy of the mass when released. This ie expressed in the following equation;
where k is the force constant of the spring, e is the compressed length, m is the mass of the block and u is the velocity with which the block leaves the spring after being released.
If we make u the subject of formula from equation (1) we obtain the following;
Given;
e = 0.105m,
k = 4825N/m,
m = 0.252kg,
u = ?
Substituting all values into equation (2) we obtain the following;
The maximum height attained is then obtained from the third equation of motion as follows, taking g as
v = 0m/s
Hence