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Solnce55 [7]
3 years ago
12

An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. The maximum speed of the o

bject is 1.15 m/s, and its maximum acceleration is 6.52 m/s2. How much time elapses between an instant when the objects speed is at a maximum and the next instant when its acceleration is at a maximum?
Physics
1 answer:
Readme [11.4K]3 years ago
5 0
<span>Object's speed is max when passing through 0 displacement.
Object's acceleration is max at either end of its oscillation, and these two times are 1/4 period apart.
y = A sin (wt)
v= Aw cos(wt)
a = - A (w^2) sin (wt)
 
v max = Aw
 a max= -A w^2
 These relations can give you w= 2 pi/ T where T = period of oscillation.</span>
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4 years ago
2. A woman prevents a 3kg brick from falling by pressing it against a vertical wall. The coefficient of friction
Anettt [7]
<h3>Answer:</h3>

49 N

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of the brick as 3 kg
  • The coefficient of friction as 0.6

We are required to determine the force that must be applied by the woman so the brick does not fall.

  • We need to importantly note that;
  • For the brick not to fall the, the force due to gravity is equal to the friction force acting on the brick.
  • That is; Friction force = Mg

But; Friction force = μ F

Therefore;

μ F = mg

0.6 F = 3 × 9.8

0.6 F = 29.4

      F = 49 N

Therefore, she must use a force of 49 N

6 0
3 years ago
Light enters an equilateral prism with an incident angle of 35° to the normal of the surface. Calculate the angle at which the
julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

n=\frac{Sini}{Sinr}

1.5=\frac{Sin35}{Sinr}

Sin r = 0.382

r = 22.5°

Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

r' = 60° - 22.5° = 37.5°

Now use Snell's law at other surface

\frac{1}{n}=\frac{Sinr'}{Sini'}

Where, i' be the angle at which the light exit from other surface.

\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}

Sin i' = 0.913

i' = 65.9°

4 0
3 years ago
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