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Solnce55 [7]
3 years ago
12

An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. The maximum speed of the o

bject is 1.15 m/s, and its maximum acceleration is 6.52 m/s2. How much time elapses between an instant when the objects speed is at a maximum and the next instant when its acceleration is at a maximum?
Physics
1 answer:
Readme [11.4K]3 years ago
5 0
<span>Object's speed is max when passing through 0 displacement.
Object's acceleration is max at either end of its oscillation, and these two times are 1/4 period apart.
y = A sin (wt)
v= Aw cos(wt)
a = - A (w^2) sin (wt)
 
v max = Aw
 a max= -A w^2
 These relations can give you w= 2 pi/ T where T = period of oscillation.</span>
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aniked [119]

Answer:

a) 46.5º  b) 64.4º

Explanation:

To solve this problem we will use the laws of geometric optics

a) For this part we will use the law of reflection that states that the reflected and incident angle are equal

     θ = 43.5º

This angle measured from the surface is

     θ_r = 90 -43.5

     θ_s = 46.5º

b) In this part the law of refraction must be used

     n₁ sin θ₁ = n₂. Sin θ₂

     sin θ₂ = n₁ / n₂ sin θ₁

The index of air refraction is n₁ = 1

The angle is this equation is measured between the vertical line called normal, if the angles are measured with respect to the surface

     θ_s = 90 - θ

     θ_s = 90- 43.5

     θ_s = 46.5º

     sin θ₂ = 1 / 1.68  sin 46.5

     sin θ₂ = 0.4318

     θ₂ = 25.6º

The angle with respect to the surface is

     θ₂_s = 90 - 25.6

     θ₂_s = 64.4º

measured in the fourth quadrant

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Answer:

no

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the answer to your question is 15 :)

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