Which two triangles are congruent? complete the congruence statement.

In the coordinate plane, point W is located at (-11,35). If point W is reflected across the x-axis, what are he new coordinates

aev [14]

Answer:

The new coordinates are (-11, -35)

Step-by-step explanation:

When reflecting across the x-axis, you are just the Y. value. It is the opposite due to the fact that if you're moving something across the horizontal x-axis, it's actually the vertical height changing. So, you just inverse the Y value to its' negative or positive reciprocal.

7 0

3 years ago

If jay ran 1 mile in 5 minutes on monday, 2 miles in 10 minutes on tuesday, and 3 miles in 15 minutes on wednesday, how many mil

BlackZzzverrR [31]

<span>If Jay continues the same pattern of running an extra mile in the extra 5 minutes each day then on Thursday you would expect him to run 4 miles in 20 minutes</span>

5 0

4 years ago

Read 2 more answers

Braxton has money in a savings account. The equation B = 800(1+0.03)'.

Stels [109]

Answer:

a) Braxton's initial investment is equals to (=) Pam's initial investment.

b)The interest on Braxton's account is less than (< ) the interest on Pam's

account.

Step-by-step explanation:

Given - Braxton has money in a savings account. The equation

B = $800(1 + 0.03)^{t}$ can be used to calculate the amount of money

in dollars, B, Braxton has in his account after t years since opening

the account. Pam also has money in a savings account. The

equation, P= $800(1 + 0.04)^{t}$ can be used to calculate the amount of

money in dollars, P, Pam has in her account after t years since

opening the account.

To find - a) Braxton's initial investment ..........Pam's initial investment.

b) The interest on Braxton's account .....the interest on Pam's

account.

Proof -

As given, Broxton equation is -

Pam equation is -

Now,

a.)

For initial investment , Put t = 0

⇒B = $800(1 + 0.03)^{0} = 800(1) = 800$

P = $800(1 + 0.04)^{0} = 800(1) = 800$

We can see that for t = 0

Initial investment of Braxton = Initial investment of Pam

⇒Braxton's Initial investment = Pam's initial investment.

b.)

For the interest,

As we have not given any time period for which the interest has to be find.

So , let the time period , t = 5 years

Therefore,

B = $800(1 + 0.03)^{5} = 800(1.03)^{5} = 800(1.159) = 927.42$

P = $800(1 + 0.04)^{5} = 800(1.04)^{5} = 800(1.217) = 973.32$

Now,

Interest on Braxton's account = 927.42 - 800 = 127.42 ≈ 127

Interest on Pam's account = 973.32 - 800 = 173.32 ≈ 173

∴ we get

The interest on Braxton's account is less than the interest on Pam's account.

7 0

3 years ago

The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax

charle [14.2K]

First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

$\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx$

Let $u=e^x$ , so that $\mathrm dx=\dfrac{\mathrm du}u$ , and the integral is equivalent to

$\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du$

The integrand is continuous everywhere except $u=0$ , but that's okay because we have $\lim\limits_{u\to0^+}\frac{\sin u}u=1$ . This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

$\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx$

By the same substitution as before, we can write this as

$\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du$

The half-angle identity for sine allows us to rewrite as

$\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du$

and replacing $v=2u$ , $\dfrac{\mathrm dv}2=\mathrm du$ , we have

$\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv$

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

$\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))$

where $\gamma$ is the Euler-Mascheroni constant and $\mbox{Ci}$ denotes the cosine integral function.

5 0

4 years ago

Plz hel p me my class is counting on me(you)

solniwko [45]

Answer:

The correct answer is D because for example...

Step-by-step explanation:

If b squared minus 4ac is non-negative, so at 0 or greater, we have at least one real solution. If it's less than 0, if it's negative, we have no real solutions!

Hope I was able to help, and I hope you Have a good day! :)

7 0

3 years ago

Which two triangles are congruent? complete the congruence statement.​

Which two triangles are congruent? complete the congruence statement.