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beks73 [17]
4 years ago
13

If jay ran 1 mile in 5 minutes on monday, 2 miles in 10 minutes on tuesday, and 3 miles in 15 minutes on wednesday, how many mil

es do you think he might run in 20 minutes on thursday?
Mathematics
2 answers:
BlackZzzverrR [31]4 years ago
5 0
<span>If Jay continues the same pattern of running an extra mile in the extra 5 minutes each day then on Thursday you would expect him to run 4 miles in 20 minutes</span>
kipiarov [429]4 years ago
3 0

Answer:

Jay might run 4 miles in 20 minutes

Step-by-step explanation:

If Jay ran on Monday = 1 mile in 5 minutes

On Tuesday = 2 miles in 10 minutes

On Wednesday = 3 miles in 15 minutes

Jay is increasing his time by 5 minutes per day and distance 1 mile per day.

So the next day Jay might run 1 mile + previous day distance in 5 minutes + time of the previous day.

Therefore, Jay might run 4 miles in 20 minutes

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Step-by-step explanation:

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3 years ago
Click
Mama L [17]

Answer:

(-3 , 0) (0, 2) (6, -6)

Step-by-step explanation:

Solving for x - intercept:

2x - 3(0) = -6

2x = -6

2x/2 = -6/2

x = -3

One point would be (-3 , 0) .

Solving for y-intercept:

2(0) - 3y = -6

-3y = -6

-3y/-3 = -6/-3

y = 2

Another point would be (0, 2).

When 'x' equals 6:

2(6) - 3y = -6

12 - 3y = -6

12 - 12 - 3y = -6 - 12

-3y = -18

-3y/3 = -18/3

y = -6

The third point would be (6, -6).

6 0
4 years ago
2.
djyliett [7]

nah it is all messed up

5 0
3 years ago
Solve this multiplication problem. Show your work 72 x 139
ohaa [14]

    139

     72

    -----

    278

+ 9730

------------

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3 0
3 years ago
Twice a number added to their half of itself equals 20 find the number
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Answer:

x(2) + 5\\

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8 0
3 years ago
Read 2 more answers
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