Answer:
An action that must be brought in the venue that has jurisdiction over the situs or is otherwise designated by law.
- P2H2 Oxidation State - Diphosphene
P2H2 has an oxidation number of +1. In P2H2, the oxidation
number of H is -1
- H2C2O4 Oxidation State - Oxalic Acid
C has an oxidation number of +3 in H2C2O4. O has an oxidation
number of -2 in H2C2O4. H2C2O4 has an oxidation number of +1.
- CrO2 Oxidation State - Chromium(IV) Oxide
CrO2 has an oxidation number of +4.
<h3>Explain oxidation?</h3>
The oxidation state, also known as the oxidation number, is an atom's hypothetical charge if all of its bonds to other atoms were fully ionic.
The sum of the oxidation states of all the atoms in an ion equals the ion's charge.
A substance's more electronegative element is given a negative oxidation state. The one that is less electronegative is given a positive oxidation state.
To learn more about oxidation refer to :
brainly.com/question/27239694
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Answer:
Velocity, u = 14.7 m/s
Explanation:
It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.
Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms
Using first equation of kinematics as :
In case of crash the final speed of the driver is, v = 0
u = 14.7 m/s
So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.
55.3C= 328.45K
255K= -18.5C
447K= 174.85C
-14C= 259.15K
