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vodka [1.7K]
2 years ago
5

If there is initially 1.334 m o2, how long will it take for the o2 concentration to reach 0.443 m?

Chemistry
1 answer:
Sedaia [141]2 years ago
3 0
To answer, we take it that the rate of the consumption of O2 in this item is directly proportional to its concentration in first degree such that, 
                       -dCa/dt  = kCa
Solving,
                    -dCa/Ca = kt
                   lnCa - lnCao = -kt
Substituting,
                   ln(0.443) - ln(1.334) = -k(t)
                            t = 1.1023/k
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B. There is a very large percentage of C-12.

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In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.

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The Lewis structures are in image attached.

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In the Lewis symbol no dot shown as magnesium has lost its 2 electrons.

Mg=1s^22s^23p^63s^2

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Calcium's atomic number is 20 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 2 electron.

Ca= 1s^22s^22p^63s^23p^64s^2

Ca^{2+}=1s^22s^23p^6^23p^64s^0

(e) K

Potassium's atomic number is 19 in which only 1 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 1 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 1 electron.

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Bromine's atomic number is 35 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet

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In the Lewis symbol no dot shown as calcium has lost its 2 electron.

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