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3 years ago

What is the average speed between 5 seconds and 15 seconds?

Physics

1 answer:

sergeinik [125]3 years ago

6 0

You didn’t include an image of any data or ahything so

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Electric charges that are different attract each other.

n200080 [17]

There are two forces between any two charges
or charged objects.

Each one exerts a force on the other one, and
the forces are equal.

If the charges are the same sign, the the forces push.

If the charges are different signs, then the forces pull.

7 0

3 years ago

Read 2 more answers

If you weighed 100 lb on Earth, what would you weigh at the upper atmosphere of Jupiter? For reference, Jupiter has a mass that

nignag [31]

Answer:

The answer to the question is

A 100 lb person would weigh 300.33 lbf at the upper atmosphere of Jupiter

Explanation:

To solve the question we note that

Mass of object = 100 lb =‪ 45.35924‬ kg

Mass of Jupiter = 300×Mass of Earth = 300×5.972 × 10²⁴ kg =1.7916×10²⁷ kg

Radius of Jupiter = 10× Radius of Earth = 10×6,371 km = 63710 km

Gravitational constant, G = 6.67408 × 10⁻¹¹ m³ kg-1 s-2

Gravitational force is given by $F_G= \frac{Gm_1m_2}{r^2}$

Plugging in the values we get

$F_G$ = $\frac{6.67408*10^{-11}*45.35924*1.7916*10^{27}}{63710^2}$ = 1335.93 N

Converting into lbf gives 1335.93 N *0.2248 lbf/N = 300.33 lbf

7 0

3 years ago

Use Kepler’s laws and the period of the Moon (27.4 d) to determine the period of an artificial satellite orbiting very near the

miv72 [106K]

As according to Kepler 's law

T =(4π²r³/ Gm)^1/2

here r= distance from earth center to satellite = 6400km = 6400000m

G = earth's gravitational constant= 6.67×10^-11

m = mass of earth= 5.98 ×10^24

so T =[ { 4× (3.1416)²×(6400000)³}/ {(6.67×10^-11)×( 5.98 ×10^24)} ]^1/2

T= 5133 sec

7 0

3 years ago

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An object is swung in a horizontal circle on a length of string

Genrish500 [490]

Answer: either 3.20s or 1.18s

Explanation:

4 0

3 years ago

A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are

RSB [31]

Answer: 6.125 ft

Explanation:

If this dish has the form of a concave upward parabola and its vertex $p$ is at the origin, its corresponding equation is:

$x^{2}=4py$

Where:

$x$ is the radius, which can be found by dividing the diameter $d=14 ft$ by half. Hence $x=\frac{d}{2}=\frac{14 ft}{2}=7 ft$

$y=2 ft$ is the depth

$p$ is the vertex of the parabola, where its base is

Finding $p$ :

$p=\frac{x^{2}}{4y}$

$p=\frac{(7 ft)^{2}}{4(2 ft)}$

Finally:

$p=6.125 ft$ This is where the the receiver should be placed

3 0

3 years ago