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natali 33 [55]
3 years ago
5

the distance between two successive troughs of wave is 0.4m. If the frequency of the source is 825Hz, calculate the speed of the

wave​
Physics
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

speed=330m/s

Explanation:

the speed of wave is given as

speed(meter per second) =frequency(hertz) * wavelength(meters)

so using the above formula we substitute the figures given in the question in the formula we get

speed = 0.4*825

speed =330m/s

note m/s is the si unit for speed which is read as meter per second

therefore speed =330m/s

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Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th
Anna71 [15]

The correct answer to the question is :  100\ ^0C

EXPLANATION :

As per the question, the specific heat of gold is given as c = 0.130\ J/g^0C

The heat given to the gold dQ = 195 J

The mass of the gold is given as m = 15 gram.

We are asked to calculate the change in temperature.

Let the change in temperature is dT.

We know that dQ = mcdT

                      dT=\ \frac{dQ}{mc}

                             =\ \frac{195}{15\times 0.130}

                             =\ 100\ ^0C                   [ANS]

Hence, the change in temperature is 100 degree celsius.

5 0
4 years ago
A wheel of radius R = 0.80 m is pulled by a rope looped around a frictionless axle. The total mass of the wheel and axle assembl
iragen [17]

Answer:

\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18

Explanation:

To find the rotational kinetic energy you first calculate the angular acceleration by using the following formula:

\tau=I\alpha\\\\FR=I\alpha\\\\\alpha=\frac{FR}{I}

F: force applied

R: radius of the wheel

I: moment of inertia

\alpha=\frac{(120N)(0.80m)}{26.88kgm^2}=3.57\frac{rad}{s^2}

With this value you calculate the angular velocity:

\omega^2=\omega_o^2+2\alpha \theta\\

you calculate how many radians the wheel run in 5.0m

\theta=\frac{2\pi (0.8m)}{5.0m}=\approx1.00rad

\omega=\sqrt{2(3.57\frac{rad}{s^2})(1.00rad)}=2.67\frac{rad}{s}

Next, you use the formula for the rotational kinetic energy:

K_R=\frac{1}{2}I\omega^2=(26.88)(2.67)^2 J = 188.63J

For the transnational kinetic energy you use the following equation:

W=\Delta K_T  (net work equals the change in the kinetic energy).

By replacing the you obtain:

\Delta K_T=Fd=(120)(5.0)J=600J

Finally, the ratio between translational rotational kinetic energy is:

\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18

hence, translational kinetic energy is three times the rotational kinetic energy.

6 0
3 years ago
Speed1=20 m/s. time1=5sec
lina2011 [118]

Answer:

<h2><em><u>2</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u>5</u></em><em><u> </u></em><em><u>m</u></em><em><u>/</u></em><em><u>s</u></em></h2>

Explanation:

<h2><em>AVERAGE</em><em> </em><em>S</em><em>P</em><em>E</em><em>E</em><em>D</em><em>=</em></h2>

<em>=  \frac{s1 t1+ s2t2 + s3t3}{t1 + t2 + t3}</em>

<em>=  \frac{20 \times 10 + 30 \times 5 + 15 \times 5}{10 + 5 + 5}</em>

<em>=  \frac{200 + 150 + 75}{20}</em>

<em>=  \frac{425}{20}</em>

<em>= 21.25 ms</em>

4 0
2 years ago
In a parallel circuit, the first resistor has a resistance of 4 Ω and a current of 4 A. The second resistor has a resistance of
9966 [12]
Voltage across 1st resistor = I x R = 16 volts
thus voltage across 3rd resistor is also 16 volts.

resistance = V/I = 16/6 =2.7 Ω
7 0
3 years ago
Using ohm's law, determine the amount of power dissipated in a 5.6k ohm resistor connected to a 5v dc source.
Karolina [17]
The equation for power is P=VI, we can then rearrange V=IR and substitute I into the equation, this gets us V/R=I. Thus we get P=V^2/R

Next we convert kΩ to Ω. This tells us the resistor in Ω is 5600Ω.

Finally, plug into equation, we get P = (5V^2)/5600Ω.

P = 0.0044642857W

Hope this helps!
8 0
3 years ago
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