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natali 33 [55]
3 years ago
5

the distance between two successive troughs of wave is 0.4m. If the frequency of the source is 825Hz, calculate the speed of the

wave​
Physics
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

speed=330m/s

Explanation:

the speed of wave is given as

speed(meter per second) =frequency(hertz) * wavelength(meters)

so using the above formula we substitute the figures given in the question in the formula we get

speed = 0.4*825

speed =330m/s

note m/s is the si unit for speed which is read as meter per second

therefore speed =330m/s

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A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of
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Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

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5 0
3 years ago
A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in
Karolina [17]

Answer:

\tau = 1256.5\ N.m

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{125.66-0}{5}

   α = 25.13 rad/s²

Torque given to the flywheel.

    \tau = I \alpha

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Torque of the given  flywheel is equal to \tau = 1256.5\ N.m

7 0
4 years ago
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